sdfgw
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| Joined: 08 Jan 2009 |
| Total Posts: 41681 |
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| 13 Nov 2012 01:19 PM |
oh no it was a trap this is THE HARDEST ALGEBRA EVER
ok but really
(x+y)^2 = (y-4)(x+4)
all you have to do is state the number of solutions (with proof morons)
if anyone can do this
i will grant them 3 wishes |
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| 13 Nov 2012 01:21 PM |
| thats impossible sdfgw stop being a idiet |
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Earth
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| Joined: 17 Jun 2007 |
| Total Posts: 19033 |
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| 13 Nov 2012 01:27 PM |
| It can't be done usin standard algibra but it can be done useing the irrational number i |
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sdfgw
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| Joined: 08 Jan 2009 |
| Total Posts: 41681 |
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| 13 Nov 2012 01:28 PM |
"It can't be done usin standard algibra"
yes
"but it can be done useing the irrational number i"
no
also i isn't irrational
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sdfgw
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| Joined: 08 Jan 2009 |
| Total Posts: 41681 |
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| 13 Nov 2012 01:28 PM |
wait that was ambiguous
you CAN do it with standard algebra
you DON'T need complex numbers |
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| 13 Nov 2012 01:33 PM |
I is a imaginary number.
And it is irrational |
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| 13 Nov 2012 01:34 PM |
| Not real numbers such as #/0 are irrational |
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| 13 Nov 2012 01:39 PM |
| It can be solved if you give another equation or a value for one of the vaiables |
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| 13 Nov 2012 01:59 PM |
Um the best I could get was (x+y)^2 = (y-4)(x+4) (x+y)^2 = y-16
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| 13 Nov 2012 02:01 PM |
| Nothing is funny about MATH. |
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| 13 Nov 2012 02:06 PM |
(x+y)^2 = (y-4)(x+4)
okay so lets foil little children
(x+y)(x+y) = xy ^2 + 4y - 4x -16
x^2 +2yx + Y^2 = xy^2 + 4y - 4x - 16
Okay brain fart |
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| 13 Nov 2012 02:07 PM |
Nope not even that
(X+y)^2= 0y |
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| 13 Nov 2012 02:07 PM |
| There is now use of negative square roots, so where did you get i from? |
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sweetie
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| Joined: 12 Oct 2006 |
| Total Posts: 11578 |
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| 13 Nov 2012 02:10 PM |
two dont feel like typing up my scratch paper thanks you very much |
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sweetie
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| Joined: 12 Oct 2006 |
| Total Posts: 11578 |
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| 13 Nov 2012 02:13 PM |
| jkbell wt r u talking about |
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| 13 Nov 2012 02:15 PM |
| Math made me fall a sleep once. |
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sdfgw
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| Joined: 08 Jan 2009 |
| Total Posts: 41681 |
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| 13 Nov 2012 02:19 PM |
@sweetie:
it's not two
"x^2 +2yx + Y^2 = xy^2 + 4y - 4x - 16"
you are on the right track at least |
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sweetie
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| Joined: 12 Oct 2006 |
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| 13 Nov 2012 02:19 PM |
oh wait if you want the solutions for the variable y
y= [-SQRT3*)SQRT-x^2-8x-16)-x+4]/2 y= [-SQRT3*(SQRTx^2-8x-16)-x+4]/2
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sweetie
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| Joined: 12 Oct 2006 |
| Total Posts: 11578 |
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| 13 Nov 2012 02:19 PM |
| wat do u want the integral solutions |
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sdfgw
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| Joined: 08 Jan 2009 |
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| 13 Nov 2012 02:20 PM |
| the solutions are simple integers mmm |
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sweetie
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| Joined: 12 Oct 2006 |
| Total Posts: 11578 |
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| 13 Nov 2012 02:21 PM |
you are mocking me i am displeased |
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sdfgw
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| Joined: 08 Jan 2009 |
| Total Posts: 41681 |
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| 13 Nov 2012 02:22 PM |
wait sweetie i see what you've done
solved for one completely in terms of the other
that's further on the right track
forgot to mention at the beginning, x and y are both real
hint hint |
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