PlusJon
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| Joined: 27 Sep 2012 |
| Total Posts: 1522 |
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| 31 Oct 2012 08:23 AM |
Ok, this question is an algebra question. I saw this when I was a freshman in high school and thought it was a good problem to practice with. Here it is:
(a-f)(b-f)(c-f)...(x-f)(y-f)(z-f) = ?
Assuming the pattern continues, what is the answer? |
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| 31 Oct 2012 08:24 AM |
1613161313517416815 is the answer
-l POTATO l- |
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PlusJon
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| Joined: 27 Sep 2012 |
| Total Posts: 1522 |
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| 31 Oct 2012 08:26 AM |
| If no one gets it soon, I'll post the answer along with an explanation. |
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| 31 Oct 2012 08:33 AM |
IDK XD :3- ANS?- (a-b-c...x-y-z)
- - - - - - - - - - - - Work out---------------- c-8 a-5 f-2 b-3 x-4 y-6 z-7 (5-2)(3-2)(8-2)...(4-2)(6-2)(7-2) 3-1-6...2-4-5 |
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PlusJon
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| Joined: 27 Sep 2012 |
| Total Posts: 1522 |
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| 31 Oct 2012 08:34 AM |
@Regigiboss
Nop.
______________________
The answer is 0.
Explanation:
You will eventually get to (f-f) which is 0. So from that point, you are multiplying by 0.
:) |
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| 31 Oct 2012 08:37 AM |
nop the answier is
-1337 becuz john da shedlatskai tripz ovar dat server cord |
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| 31 Oct 2012 08:37 AM |
| Well I tried my best im only grade 6 XD |
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