sigh3192
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| Joined: 24 Oct 2009 |
| Total Posts: 4245 |
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| 23 Aug 2012 12:25 AM |
This is a combination of I, Dr. Snooty mc Snoot Snoot, and Dr.Richy8447 Hopkins
I combined my Gnomeish Equation with his Dwarven Equation after noticing similarites and we came up with something we called the Frodo Effect! Lets take a look!
So everything is about gnomes so we start with the basic gnome equation: 3x X y^4-3(x^4)=-131 3(x^4)-y^4=131
[3^1/2 (x^2)]^2 - [y^2]^2=131 {[left]-[right]}{[left]+[right]}=131 --------expression (A^8) the {[left]+[right]} =5k
Therefore:
IF: x and y were positive integers then x^2 and y^2 would also be integers, SQRT(3) is not an integer, therefore (x^2)(sqrt(3)) cannot be an integer
we can expand {[left]-[right]} again as difference of squares
{(3^1/4)(x)}^2-y^2}= [3^1/4(x)-y][3^1/4+y] so we have - using "int" for integer and "non" for non integer, [non-int]=non [non+int]=non
So, in (A) we have, (non)(non)(non)=131
The fractional part of the first and second (non) is the fractional part of the root of 3 but the integer part is different so, it will not produce an integer. The fractional part of the third (non) is the fractional part of sqrt of 3 so, it will not produce an integer when multiplied with the first 2 (non). Therefore, these (non)(non)(non) will not produce an integer. But 131 is an integer. It follows that our initial supposition about x and y was not valid.
Therefore since x and y are not valid in there original form that means we can cross reference the magic beans inside Gnomish blood to discover the Dwarf effect which is :
If sin2x=22 - 8√7 Prove that 3(Sinx+Cosx+Tanx+Cosecx+Secx+Cotx) =21
Let sin 2x = k
k = 22- 8√7
k - 22 = -8√7 [Bring 22 to the LHS)
(k-22)² = (-8√7)²
k² - 44k + 484 = 448
k² - 44k = 448-484
k² - 44k = -36
k³ - 44k² = -36k
k³ - 44k² + 36k = 0 [Bringing -36k to the LHS]
k³ - 49k² +5k² + 8k + 28k = 0 k³ + 5k² + 8k = 49k² - 28k
k³ + 4k² + k² + 4k + 4k = 49k² - 28k [Rearranging factors]
k³ + 4k² + k² + 4k + 4k + 4 - 4 = 49k² - 28k [Adding + 4 and -4 to make it a quadratic/polynomial]
k³ + 4k² + k² + 4k + 4k + 4 = 49k² - 28k + 4 [Bringing -4 to the RHS]
k³ + 4k² + k² + 4k + 4k + 4 = (7k - 2)² [Writing 49k² - 28k + 4 in the form of (a-b)²]
(1+k)(k² + 4k + 4) = (7k - 2)² [Factoring LHS]
(1+k)(k + 2)² = (7k - 2)² [Writing k² + 4k + 4 in the form of (a+b)²]
(1+k) = (7k-2)²/(k+2)² [Bringing (k+2)² to the RHS]
(1 + 2sinxcosx) = (7k-2)²/(k+2)² [k = sin2x = 2sinxcosx]
(sin²x + cos²x + 2sinxcosx) = (7k-2)²/(k+2)² [ 1 = sin²x + cos²x and we bring LHS to the form (a+b)²]
(sinx + cosx)² = (7k-2)²/(k+2)²
(sinx + cosx) = (7k-2)/(k+2) [amount of gnomes affected in the war)
sinx + cosx = (7k -2)/k / (k+2)/k) (K = Kingmar Dwraves)
sinx + cosx = (7 - 2/k) / (1+2/k)
(sinx + cosx) (1 + 2/k) = 7 - 2/k [Taking (1+2/k) to the LHS]
sinx + cosx + 2sinx/k + 2cosx/k = 7 - 2/k (Nearly an army of dwarves)
sinx + cosx + 2/k(sinx + cosx) + 2/k = 7 (How many dwarves snow white had)
sinx + cosx + 2/k(sinx + cosx + 1) = 7 (How many dwarves snow white had)
sinx + cosx + 2/k(sinx + cosx + sin²x + cos²x) = 7 [ 1 = sin²x + cos²x]
sinx + cosx + 2/2sinxcos (sinx + cosx + sin²x + cos²x) = 7 [k = sin2x = 2sinxcosx]
sinx + cosx + 1/cosx + 1/sinx + sinx/cosx + cosx/sinx = 7 [SNOW WHITE)
sinx+cosx+secx+cosecx+tanx+cotx = 7 [1/cosx=secx,1/sinx=cosecx,sinx/cosx=tan…
Therefore sinx + cosx + secx + cosecx + tanx + cotx = 7
3(sinx + cosx + secx + cosecx + tanx + cotx) = 21
therefore 21 equals the number of dwarves it takes to successfully take over all the other forums.
Therefore we do some simple algebra
10² + 11² + 12² = 13² + 14² = 365/nx+cosx+secx+cosecx+tanx+cotx = 7 [1/cosx=secx,1/sinx=cosecx,sinx/cosx=tan…
Therefore sinx + cosx + stuff.
This means that if we use the Jupiter Cable to Cross Loop the magic beans in gnomish blood with dwarven radiation we could turn everyone into frodo.
THAT is the Frodo Effect
By Sigh3192 and Richy8557/Richy8447 |
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Zegion1
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| Joined: 06 Nov 2011 |
| Total Posts: 2814 |
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Richy8557
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| Joined: 14 Jun 2012 |
| Total Posts: 980 |
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Dathuran
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| Joined: 13 Jun 2012 |
| Total Posts: 1720 |
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| 23 Aug 2012 12:30 AM |
wait wat
let me get a calculator
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Richy8557
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| Joined: 14 Jun 2012 |
| Total Posts: 980 |
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| 23 Aug 2012 12:30 AM |
| hurry add in the 42 quick11111 the time seam is opening1111 |
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