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Re: I have an easy problem

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PsychoBob is not online. PsychoBob
Joined: 08 Jul 2009
Total Posts: 11047
19 Aug 2012 02:23 AM
Find the flux through a surface described as:
z = x²y-2xy+x-5y
0 < x < 3
0 < y < 3
With a vector field described as:
v(p, q, r) = pq[1, 0, 0] + (q²-p sin r)[0, 1, 0] + (s² + cos r cos p sin s)[0, 0, 1]

If anyone can even set up the proper flux integral I'll be more than impressed already
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700gb is not online. 700gb
Joined: 08 Feb 2011
Total Posts: 7503
19 Aug 2012 02:24 AM
We'll get the anwser right after these messages!
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PsychoBob is not online. PsychoBob
Joined: 08 Jul 2009
Total Posts: 11047
19 Aug 2012 02:33 AM
Oh come on

None of you can even do the parametrization?
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vienna456 is not online. vienna456
Joined: 12 Sep 2010
Total Posts: 15043
19 Aug 2012 02:39 AM
Do your own homework.....lol
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vienna456 is not online. vienna456
Joined: 12 Sep 2010
Total Posts: 15043
19 Aug 2012 02:41 AM
we could do it for you.....but then how would you learn...






lol
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PsychoBob is not online. PsychoBob
Joined: 08 Jul 2009
Total Posts: 11047
19 Aug 2012 02:42 AM
Alright, I'll at least get you started on the parametrization

The nice things about polynomial regions is that they parametrize incredibly easily

x = u
y = v
z = u²v - 2uv + u - 5v

So now we can make a vector valued function

F(x(u,v), y(u, v), z(u, v)) = u[1, 0, 0] + v[0, 1, 0] + (u²v - 2uv + u - 5v)[0, 0, 1]
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SuperTrailMix is not online. SuperTrailMix
Joined: 26 Jul 2011
Total Posts: 402
19 Aug 2012 02:43 AM
Sir, are you copy and pasting?
it seems as if you are

Dr. Kuku, Scientist of OT
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PsychoBob is not online. PsychoBob
Joined: 08 Jul 2009
Total Posts: 11047
19 Aug 2012 02:45 AM
@Super

Believe it or not

I'm not

I do actually know all of this stuff and I am way too old for these forums
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spot is not online. spot
Joined: 29 Dec 2006
Total Posts: 37193
19 Aug 2012 02:49 AM
im lazy
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pieman1026 is not online. pieman1026
Joined: 23 Jan 2010
Total Posts: 45769
19 Aug 2012 02:50 AM
eh

AND I WAS LIKE, "YO DARTHNECRON, I'M COMIN FOR YOUR LOTION HOMIE"
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