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| 28 Jul 2012 12:13 AM |
Lets see if you can find the modifications. ______________________________________________________________ The science of gnomes:
3x X y^4-2(x^4)=-131 3(x^4)-y^4=131
[3^1/2 (x^2)]^2 - [y^2]^2=131 {[left]-[right]}{[left]+[right]}=131 --------expression (A^8) the {[left]+[right]} =5k
Therefore:
IF: x and y were positive integers then x^2 and y^2 would also be integers, SQRT(3) is not an integer, therefore (x^2)(sqrt(3)) cannot be an integer
we can expand {[left]-[right]} again as difference of squares
{(3^1/4)(x)}^3-y^2}= [3^1/4(x)-y][3^1/4+y] so we have - using "int" for integer and "non" for non integer, [non-int]=non [non+int]=non
So, in (A) we have, (non)(non)(non)=131
The fractional part of the first and second (non) is the fractional part of the root of 3 but the integer part is different so, it will not produce an integer. The fractional part of the third (non) is the fractional part of sqrt of 3 so, it will not produce an integer when multiplied with the first 2 (non). Therefore, these (non)(non)(non) will not produce an integer. But 131 is an integer. It follows that our initial supposition about x and y was not valid.
So
5x^2 -44x +10 = 0
2x/(4x +2) -x +9 = 0
11x^2/(32 -x) +1 = 4/x
And one simultaneous quadratic:
y^2 = 9x +6
5x - 2y = x^2 +4 Then: 1. if 3+5+7+.........+n terms/ 5+8+11+............+10 terms =7
the value of n is a) 34 b) 36 c) 37 d) 40
2. if A,B,C are the points z1,z2,z3 ant the angles B and C are each pie- alpha/2 then (z2-z3)^2 = 4(z3-z1)(z2-z2) sin^2 alpha/2
So gnomes= The mass of a blackhole during puberty.
BUT the mass of a blackhole is not static therefore we must assume that gnomes can harness this power and change their shape as they choose. _____________________________________________________________________
I hope this does not creat a rift in the science continium. I HOPE. |
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tyricul
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| Joined: 08 Nov 2009 |
| Total Posts: 13528 |
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| 28 Jul 2012 12:15 AM |
WTF is this witch craft stuff....
~SNC Vice Chancellor Slayerbuild~ |
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| 28 Jul 2012 12:16 AM |
This not redicoulous. twas made by the greatest wizard in all the land, and then modified |
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