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Re: The dwarf equations

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richy8447 is not online. richy8447
Joined: 28 Jan 2010
Total Posts: 6222
27 Jul 2012 11:38 PM
x2 + y1 = m
M - a1 = f
F = 15

So therefore dwarf = 97

See my logic?
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darkprimal is not online. darkprimal
Joined: 17 Feb 2011
Total Posts: 3393
27 Jul 2012 11:39 PM
you just want to be like sigh.
you will never top his skill
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richy8447 is not online. richy8447
Joined: 28 Jan 2010
Total Posts: 6222
27 Jul 2012 11:39 PM
Wait who?
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sigh3192 is not online. sigh3192
Joined: 24 Oct 2009
Total Posts: 4245
27 Jul 2012 11:39 PM
The science of gnomes:

3x X y^4-3(x^4)=-131
3(x^4)-y^4=131

[3^1/2 (x^2)]^2 - [y^2]^2=131
{[left]-[right]}{[left]+[right]}=131 --------expression (A^8)
the {[left]+[right]} =5k

Therefore:

IF: x and y were positive integers then x^2 and y^2 would also be integers,
SQRT(3) is not an integer, therefore (x^2)(sqrt(3)) cannot be an integer

we can expand {[left]-[right]} again as difference of squares

{(3^1/4)(x)}^2-y^2}= [3^1/4(x)-y][3^1/4+y]
so we have - using "int" for integer and "non" for non integer,
[non-int]=non
[non+int]=non

So, in (A) we have, (non)(non)(non)=131

The fractional part of the first and second (non) is the fractional part of the root of 3 but the integer part is different so, it will not produce an integer.
The fractional part of the third (non) is the fractional part of sqrt of 3 so, it will not produce an integer when multiplied with the first 2 (non).
Therefore, these (non)(non)(non) will not produce an integer. But 131 is an integer. It follows that our initial supposition about x and y was not valid.

So


5x^2 -45x +10 = 0

2x/(4x +2) -x +9 = 0

12x^2/(32 -x) +1 = 4/x

And one simultaneous quadratic:

y^2 = 10x +6

5x - 2y = x^2 +4
Then:
1.
if 3+5+7+.........+n terms/ 5+8+11+............+10 terms =7

the value of n is
a) 35 b) 36 c) 37 d) 40

2. if A,B,C are the points z1,z2,z3 ant the angles B and C are each pie- alpha/2
then
(z2-z3)^2 = 4(z3-z1)(z1-z2) sin^2 alpha/2

So gnomes= The mass of a blackhole during puberty.


BUT the mass of a blackhole is not static therefore we must assume that gnomes can harness this power and change their shape as they choose.
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HardCoreRecon is not online. HardCoreRecon
Joined: 23 Aug 2010
Total Posts: 3379
27 Jul 2012 11:40 PM
Where exactly does dwarf enter the equation here?
All you showed is that the *F* is dwarf is equivalent to 15.
What about *D*, *W*, *A*, and *R*?

 - Cubyfan2
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richy8447 is not online. richy8447
Joined: 28 Jan 2010
Total Posts: 6222
27 Jul 2012 11:41 PM
You forgot to input the desisive factor of evil gnomes, dwarves and warrior monkies...

Therefor gnomes = the mass of TWO black holes during puberty
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TDFall is not online. TDFall
Joined: 07 May 2009
Total Posts: 16218
27 Jul 2012 11:41 PM
wat
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HardCoreRecon is not online. HardCoreRecon
Joined: 23 Aug 2010
Total Posts: 3379
27 Jul 2012 11:41 PM
WTF did I just read?

 - Cubyfan2
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taylordeathwolf is not online. taylordeathwolf
Joined: 03 Feb 2011
Total Posts: 1949
27 Jul 2012 11:42 PM
i should stay out of this junk
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sigh3192 is not online. sigh3192
Joined: 24 Oct 2009
Total Posts: 4245
27 Jul 2012 11:42 PM
BUT The mass of a blackhole is not static and two black holes in a binary hole is even less static. Therefore warrior monkeys would turn into gnomes. Dwarves are extinct, and all gnomes are evil. So your argument is invalid.
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darkprimal is not online. darkprimal
Joined: 17 Feb 2011
Total Posts: 3393
28 Jul 2012 12:05 AM
sigh wins
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gokured1234567 is not online. gokured1234567
Joined: 17 Aug 2011
Total Posts: 7778
28 Jul 2012 12:06 AM
I'm pretty, sure my mind has been violated.....
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Notom is not online. Notom
Joined: 18 Nov 2008
Total Posts: 5108
28 Jul 2012 12:08 AM
did i just get mindrped?

◙WAT U GON DOO?◙
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Flammus is online. Flammus
Joined: 26 Aug 2011
Total Posts: 50727
28 Jul 2012 12:08 AM
erm
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Bcs54 is not online. Bcs54
Joined: 19 Sep 2009
Total Posts: 1873
28 Jul 2012 12:08 AM
O_o
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darkprimal is not online. darkprimal
Joined: 17 Feb 2011
Total Posts: 3393
28 Jul 2012 12:09 AM
me an sigh,
bringing genious equations to you.
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gokured1234567 is not online. gokured1234567
Joined: 17 Aug 2011
Total Posts: 7778
28 Jul 2012 12:09 AM
OMG MADONNA, CAN'T EVEN FIGURE THIS OUT HAX!
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gokured1234567 is not online. gokured1234567
Joined: 17 Aug 2011
Total Posts: 7778
28 Jul 2012 12:10 AM
If only "Honeydew" was, here he would know what to do =\
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eletrowiz is not online. eletrowiz
Joined: 08 Dec 2008
Total Posts: 12438
28 Jul 2012 12:11 AM
Summary; some people have a lot of imaginations making up equations.
The chances of this can be represented as F^2
If F = AC^2/CD*GH
We can quickly see that it is the same odds of a troll being under a bridge.
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gokured1234567 is not online. gokured1234567
Joined: 17 Aug 2011
Total Posts: 7778
28 Jul 2012 12:12 AM
Uh........
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gokured1234567 is not online. gokured1234567
Joined: 17 Aug 2011
Total Posts: 7778
28 Jul 2012 12:13 AM
Ya.... what "eletrowiz" said.
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darkprimal is not online. darkprimal
Joined: 17 Feb 2011
Total Posts: 3393
28 Jul 2012 12:14 AM
but trolls are real,
this is proved many times on the internet
shall i sit under a bridge?
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