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sigh3192 is not online. sigh3192
Joined: 24 Oct 2009
Total Posts: 4245
18 Jun 2012 09:18 PM
Me: God, can you PLEASE stop my dad from dying?

God: Shuddup! I'm busy deciding who will win the superbowl!

Me: sadfaic :(
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deceptional is not online. deceptional
Joined: 20 May 2012
Total Posts: 18040
18 Jun 2012 09:19 PM
sadfaic + :( = (:


invalid
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fooger is not online. fooger
Joined: 27 Oct 2008
Total Posts: 7185
18 Jun 2012 09:20 PM
Best of luck to your dad, my good neighbor passed away today.
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Speedycub100 is not online. Speedycub100
Joined: 26 Jul 2011
Total Posts: 6630
18 Jun 2012 09:20 PM
praying.
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GGGGG14 is not online. GGGGG14
Joined: 29 Jan 2012
Total Posts: 25344
18 Jun 2012 09:22 PM
Keep praying and you gonna be in twuble. :3
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DarkGuyNumber1 is not online. DarkGuyNumber1
Joined: 04 Oct 2011
Total Posts: 128
18 Jun 2012 09:23 PM
I'm going to pray to Satan for your dad.
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YeIIoJaket is not online. YeIIoJaket
Joined: 29 Aug 2010
Total Posts: 13436
18 Jun 2012 09:23 PM
"Shuddup! I'm busy deciding who will win the superbowl!"

>Two teams for the Super Bowl in 2013 are already chosen.
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Wowgnomes is not online. Wowgnomes
Joined: 27 Sep 2009
Total Posts: 26255
18 Jun 2012 09:24 PM
[ Content Deleted ]
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The13thHippie is not online. The13thHippie
Joined: 18 May 2010
Total Posts: 47856
18 Jun 2012 09:25 PM
Even as a joke, this was not funny at all.
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elite6247 is not online. elite6247
Joined: 13 Jun 2010
Total Posts: 13041
18 Jun 2012 09:27 PM
What 13th said.

Don't even try and make God appear like that.
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sigh3192 is not online. sigh3192
Joined: 24 Oct 2009
Total Posts: 4245
18 Jun 2012 09:28 PM
Sorry, I must have done the math wrong. Let me recalculate.

a = c = 0, b = 5, and d = 4. Thus, p = 0. The cubic equation (6) is


The three real roots are -2, 2, 5/2. However, we must select q = 5/2 in order to satisfy equation (5). Then e2 = 5 - 5 = 0 and f2 = 25/4 - 4 = 9/4, giving e = 0 and f = 3/2. The quadratic equations (7) become x2 + 4 = 0 and x2 + 1 = 0, yielding the four roots to the original polynomial, x = -i, i, -2i, 2i.

Then
-2, 2, -5/2, say q = 2. Then e2 = 4 + 5 = 9 and f2 = 4 - 4 = 0, giving e = 3 and f = 0. The quadratic equations (7) become

therefore

procedure Quadratic_Equation is
type Roots is array (1..2) of Float;
function Solve (A, B, C : Float) return Roots is
SD : constant Float := sqrt (B**2 - 4.0 * A * C);
X : Float;
begin
if B < 0.0 then
X := (- B + SD) / 2.0 * A;
return (X, C / (A * X));
else
X := (- B - SD) / 2.0 * A;
return (C / (A * X), X);
end if;
end Solve;

R : constant Roots := Solve (1.0, -10.0E5, 1.0);
begin
Put_Line ("X1 =" & Float'Image (R (1)) & " X2 =" & Float'Image (R (2)));
end Quadratic_Equation;


So..

The notation is due to Legendre. If the real part of the complex number z is positive (Re(z) > 0), then the integral

converges absolutely. Using integration by parts, we see that the gamma function satisfies the functional equation:

Combining this with , we get:

for all positive integers n.


The absolute value of the gamma function on the complex plane.
The identity Γ(z) = Γ(z+1) / z can be used (or, yielding the same result, analytic continuation can be used) to extend the integral formulation for Γ(z) to a meromorphic function defined for all complex numbers z, except z = −n for integers n ≥ 0, where the function has simple poles with residue (−1)n/n!.
It is this extended version that is commonly referred to as the gamma function.
[edit]Alternative definitions
The following infinite product definitions for the gamma function, due to Euler and Weierstrass respectively, are valid for all complex numbers z, except the non-positive integers:

where is the Euler–Mascheroni constant. It is straightforward to show that the Euler definition satisfies the functional equation (1) above.
A somewhat curious parametrization of the gamma function is given in terms of generalized Laguerre polynomials,
which converges for Re(z) < 1/2.

[edit]The gamma function in the complex plane
The behavior of for an increasing positive variable is simple: it grows quickly — faster than an exponential function. Asymptotically as , the magnitude of the gamma function is given by Stirling's formula

where the symbol ~ means that the quotient of both sides converges to 1.
The behavior for nonpositive z is more intricate. Euler's integral does not converge for z ≤ 0, but the function it defines in the positive complex half-plane has a unique analytic continuation to the negative half-plane. One way to find that analytic continuation is to use Euler's integral for positive arguments and extend the domain to negative numbers by repeated application of the recurrence formula,

choosing n such that z + n is positive. The product in the denominator is zero when z equals any of the integers 0, −1, −2,... . Thus, the gamma function must be undefined at those points due to division by zero; it is a meromorphic function with poles at the nonpositive integers. The following image shows the graph of the gamma function along the real line:

The gamma function is nonzero everywhere along the real line, although it comes arbitrarily close as . There is in fact no complex number z for which , and hence the reciprocal gamma function is an entire function, with zeros at z = 0, −1, −2,.... We see that the gamma function has a local minimum at where it attains the value . The gamma function must alternate sign between the poles because the product in the forward recurrence contains an odd number of negative factors if the number of poles between and is odd, and an even number if the number of poles is even.
Plotting the gamma function in the complex plane yields:

Absolute value



Real part



Imaginary part


Which means that saidfaic(2) multiplied by the variable pull of a black hole, +
:( to the fifth power of a gregarian equations along with the ultimate mass of a fat guy = SADFAICx5
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BerserkTurtles is not online. BerserkTurtles
Joined: 23 Jul 2010
Total Posts: 12387
18 Jun 2012 09:29 PM
Give a man a fish and he is fed for one day
Teach a man to fish and he is fed for a lifetime
Teach a man to pray and he dies praying for food
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sigh3192 is not online. sigh3192
Joined: 24 Oct 2009
Total Posts: 4245
18 Jun 2012 09:33 PM
Berserk,


[(3!)!]!
==> [(3 * 2)!]!
==> [6 * 5 * 4 * 3 * 2]!
==> 720!

720 * 719 * 718 * ... * 3 * 2 * 1

720 / 5 = 144 factors of 5
720 / 25 = 28 factors of 25
720 / 125 = 5 factors of 125
720 / 625 = 1 factor of 625

Therefore, [(3!)!]! has 144 + 28 + 5 + 1 = 178 trailing zeroes.

Therefore we can determine that a man that prays will have a fish fall on his head. Trailed by 178 zeroes.
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Wowgnomes is not online. Wowgnomes
Joined: 27 Sep 2009
Total Posts: 26255
18 Jun 2012 09:34 PM
[ Content Deleted ]
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sigh3192 is not online. sigh3192
Joined: 24 Oct 2009
Total Posts: 4245
18 Jun 2012 09:35 PM
:O
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Wowgnomes is not online. Wowgnomes
Joined: 27 Sep 2009
Total Posts: 26255
18 Jun 2012 09:36 PM
[ Content Deleted ]
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gerry12 is not online. gerry12
Joined: 25 Jul 2009
Total Posts: 2988
18 Jun 2012 09:36 PM
So ..........who will win the superbowl.
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sigh3192 is not online. sigh3192
Joined: 24 Oct 2009
Total Posts: 4245
18 Jun 2012 09:39 PM
The Patriots
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DarkLadyvanStar is not online. DarkLadyvanStar
Joined: 19 Nov 2011
Total Posts: 936
18 Jun 2012 09:40 PM
I'd burn from acid from inside out...

nln_(^~^)_lml ~DarkLadyvanStar~
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GGGGG14 is not online. GGGGG14
Joined: 29 Jan 2012
Total Posts: 25344
18 Jun 2012 09:47 PM
This subject matter is not funny even if it is a joke, though. You realize that you are insulting the almighty in public.
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sigh3192 is not online. sigh3192
Joined: 24 Oct 2009
Total Posts: 4245
18 Jun 2012 09:48 PM
Are you calling me a liar?
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