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f(x) = (x-4)/(2x+1) ; Find the...

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blocks878 is not online. blocks878
Joined: 22 Jul 2008
Total Posts: 18271
26 Nov 2011 02:21 PM
Domain,
Vertical Asymptote,
Horizontal Asymptote.

Go!
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spookyBen is not online. spookyBen
Joined: 13 Dec 2009
Total Posts: 6581
26 Nov 2011 02:22 PM
the first equation is equal to 3 so the other one must be " 1+ 1+1 or 2+ 1+ 0 or 3 +0
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blocks878 is not online. blocks878
Joined: 22 Jul 2008
Total Posts: 18271
26 Nov 2011 02:22 PM
Find the x-intercept too. :)
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blocks878 is not online. blocks878
Joined: 22 Jul 2008
Total Posts: 18271
26 Nov 2011 02:23 PM
It's only one part. It's a rational function.
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ProfessorPoophead is not online. ProfessorPoophead
Joined: 22 Nov 2011
Total Posts: 1081
26 Nov 2011 02:24 PM
i take 9th grade algebra and i'm in 8th grade..

what is this..?! im gonna sue my algebra teacher LOL
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SchoolSuxsoMUCH is not online. SchoolSuxsoMUCH
Joined: 04 Nov 2011
Total Posts: 133
26 Nov 2011 02:25 PM
ummm....err aahh.......uh.......uhmmm...erm.....uhh......27!
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blocks878 is not online. blocks878
Joined: 22 Jul 2008
Total Posts: 18271
26 Nov 2011 02:25 PM
This is pre-calc. :D
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ProfessorPoophead is not online. ProfessorPoophead
Joined: 22 Nov 2011
Total Posts: 1081
26 Nov 2011 02:26 PM
@blocks878

when do i get to take calculus? o3o
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blocks878 is not online. blocks878
Joined: 22 Jul 2008
Total Posts: 18271
26 Nov 2011 02:27 PM
If you're done with pre-calc. It depends on when you finish a particular math course. Maybe 12th grade.
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blocks878 is not online. blocks878
Joined: 22 Jul 2008
Total Posts: 18271
26 Nov 2011 02:48 PM
Anyone figured it out? :D
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blocks878 is not online. blocks878
Joined: 22 Jul 2008
Total Posts: 18271
26 Nov 2011 03:03 PM
Okay here are the solutions.

X-INTERCEPT:
To find the x-intercept, just set the numerator equal to zero, because 0 in the numerator makes the whole function equal to zero. This is where it crosses the x-axis.

so, this case,
x-4 = 0
x = 4

So the x-intercept is (4,0).
----------------------------------------------------------------------------------------------
DOMAIN:
To find the domain, we must figure out which numbers are restricted in the function. So, we know 0 cannot exist in the denominator, because that will make the function undefined.

so, we set the denominator equal to zero.
2x + 1 = 0
2x = -1
x = -1/2 -> x =/= -1/2

So the domain is ALL REAL NUMBERS EXCEPT -1/2.
--------------------------------------------------------------------------------------------
VERTICAL ASYMPTOTE:
Whenever there is an undefined value, there will be a vertical asymptote. -1/2 is undefined.
So a vertical asymptote will exist at the line, x = -1/2
--------------------------------------------------------------------------------------------
HORIZONTAL ASYMPTOTE:
Since the leading term as the same exponent (1), then the horizontal asymptote is
y = (numerator's leading term coefficient)/(denominator's leading term coefficient)

Numerator's leading term = x
Denominator's leading term = 2x

Forget the x's and focus on the number. Divide the number.
So the horizontal asymptote is the line, y= 1/2
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