blocks878
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| Joined: 22 Jul 2008 |
| Total Posts: 18271 |
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| 26 Nov 2011 02:21 PM |
Domain, Vertical Asymptote, Horizontal Asymptote.
Go! |
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spookyBen
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| Joined: 13 Dec 2009 |
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| 26 Nov 2011 02:22 PM |
| the first equation is equal to 3 so the other one must be " 1+ 1+1 or 2+ 1+ 0 or 3 +0 |
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blocks878
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| Joined: 22 Jul 2008 |
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| 26 Nov 2011 02:22 PM |
| Find the x-intercept too. :) |
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blocks878
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| Joined: 22 Jul 2008 |
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| 26 Nov 2011 02:23 PM |
| It's only one part. It's a rational function. |
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| 26 Nov 2011 02:24 PM |
i take 9th grade algebra and i'm in 8th grade..
what is this..?! im gonna sue my algebra teacher LOL |
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| 26 Nov 2011 02:25 PM |
| ummm....err aahh.......uh.......uhmmm...erm.....uhh......27! |
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blocks878
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| Joined: 22 Jul 2008 |
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| 26 Nov 2011 02:26 PM |
@blocks878
when do i get to take calculus? o3o |
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blocks878
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| Joined: 22 Jul 2008 |
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| 26 Nov 2011 02:27 PM |
| If you're done with pre-calc. It depends on when you finish a particular math course. Maybe 12th grade. |
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blocks878
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blocks878
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| Joined: 22 Jul 2008 |
| Total Posts: 18271 |
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| 26 Nov 2011 03:03 PM |
Okay here are the solutions.
X-INTERCEPT: To find the x-intercept, just set the numerator equal to zero, because 0 in the numerator makes the whole function equal to zero. This is where it crosses the x-axis.
so, this case, x-4 = 0 x = 4
So the x-intercept is (4,0). ---------------------------------------------------------------------------------------------- DOMAIN: To find the domain, we must figure out which numbers are restricted in the function. So, we know 0 cannot exist in the denominator, because that will make the function undefined.
so, we set the denominator equal to zero. 2x + 1 = 0 2x = -1 x = -1/2 -> x =/= -1/2
So the domain is ALL REAL NUMBERS EXCEPT -1/2. -------------------------------------------------------------------------------------------- VERTICAL ASYMPTOTE: Whenever there is an undefined value, there will be a vertical asymptote. -1/2 is undefined. So a vertical asymptote will exist at the line, x = -1/2 -------------------------------------------------------------------------------------------- HORIZONTAL ASYMPTOTE: Since the leading term as the same exponent (1), then the horizontal asymptote is y = (numerator's leading term coefficient)/(denominator's leading term coefficient)
Numerator's leading term = x Denominator's leading term = 2x
Forget the x's and focus on the number. Divide the number. So the horizontal asymptote is the line, y= 1/2
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