LordNavy1
|
  |
| Joined: 12 Aug 2011 |
| Total Posts: 172 |
|
| |
|
| |
|
smilex
|
  |
| Joined: 23 Sep 2008 |
| Total Posts: 21222 |
|
| |
|
| |
|
| |
|
Bombz99
|
  |
| Joined: 14 Nov 2010 |
| Total Posts: 62362 |
|
|
| 25 Sep 2011 06:19 PM |
238938925790345690235620356023
Pay up. |
|
|
| Report Abuse |
|
|
| |
|
| |
|
| |
|
|
| 25 Sep 2011 06:20 PM |
Not possible so answer =?
ohider |
|
|
| Report Abuse |
|
|
|
| 25 Sep 2011 06:20 PM |
| z=x+y. Z can be ANY number, because X and Y can be ANY number. You pay me now? |
|
|
| Report Abuse |
|
|
| |
|
|
| 25 Sep 2011 06:20 PM |
| Wait, when did ROBLOX have math? :? |
|
|
| Report Abuse |
|
|
LordNavy
|
  |
| Joined: 21 Apr 2011 |
| Total Posts: 32651 |
|
| |
|
| |
|
| |
|
smilex
|
  |
| Joined: 23 Sep 2008 |
| Total Posts: 21222 |
|
|
| 25 Sep 2011 06:21 PM |
| commander is technically the only valid answer. Since there are no variable or numbers to base z off of, the only possible solution with the information is z = z. |
|
|
| Report Abuse |
|
|
AfroSlice
|
  |
| Joined: 12 Jun 2011 |
| Total Posts: 5023 |
|
|
| 25 Sep 2011 06:21 PM |
x=a
or.. Cant be done, not a proper math problem.
- Ä£rö§lï¢ê ツ |
|
|
| Report Abuse |
|
|
|
| 25 Sep 2011 06:21 PM |
| Z can be anu number, because X and Y are not defined. |
|
|
| Report Abuse |
|
|
arkia99
|
  |
| Joined: 25 Aug 2008 |
| Total Posts: 1463 |
|
|
| 25 Sep 2011 06:21 PM |
If x=y that means z=a
OR z= Now I know my abc's, won't you sing wih me?
OR z= z (2) |
|
|
| Report Abuse |
|
|
| |
|
| |
|
LordNavy
|
  |
| Joined: 21 Apr 2011 |
| Total Posts: 32651 |
|
|
| 25 Sep 2011 06:22 PM |
| random, can't it also be imaginary? |
|
|
| Report Abuse |
|
|
|
| 25 Sep 2011 06:22 PM |
x = {q + [q2 + (r-p2)3]1/2}1/3 + {q - [q2 + (r-p2)3]1/2}1/3 + p
p = -b/(3a), q = p3 + (bc-3ad)/(6a2), r = c/(3a) |
|
|
| Report Abuse |
|
|
| |
|