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| 22 Sep 2011 06:44 PM |
| You wouldn't happen to know how to find the value of g prime of 1 when g is the inverse of the function f defined by f(x) = 2x^3 - 3/x, would you? I'm stuck on this one. |
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TheOldays
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| Joined: 29 Jun 2010 |
| Total Posts: 156 |
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| 22 Sep 2011 06:48 PM |
GOOD LORD. NO ONE KNOWS CALCULUS?????
This is just implicit differentiation. Seriously, guys. Come on. |
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HeyOT
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| Joined: 12 Sep 2011 |
| Total Posts: 1342 |
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| 22 Sep 2011 06:48 PM |
| hey dude whats 5 + 6 i'm having trouble |
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pivotmana
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| Joined: 13 Sep 2008 |
| Total Posts: 1382 |
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| 22 Sep 2011 06:49 PM |
Nowadays, once someone reaches Sophmore year, they quit ROBLOX because usually everyone quits by then.
So, you're all alone, son. |
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moose1997
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| Joined: 04 Jul 2008 |
| Total Posts: 12502 |
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C0M4
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| Joined: 15 Sep 2011 |
| Total Posts: 337 |
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| 22 Sep 2011 06:49 PM |
| Considering that I'm only in 8th grade, I cannot answer that. |
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| 22 Sep 2011 06:49 PM |
| Moose, I'm not actually that old. XD WHY CANT U GUYS HELP ME? |
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magma72
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| Joined: 23 Jun 2010 |
| Total Posts: 5114 |
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| 22 Sep 2011 06:53 PM |
Well first off, no one knows what x is and second of all, NO ONE WANTS TO HELP YOU!!!!!!!!!!!!!
-Good for you-
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| 22 Sep 2011 07:01 PM |
f'(x)=2x^3-3/x
f'(x)= I forgot how to do this. |
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| 22 Sep 2011 07:03 PM |
| Um...see, I'm taking CP Geometry, so I can't help you... |
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| 22 Sep 2011 07:06 PM |
| I'm going to review and then solve the problem. |
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