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| 22 Sep 2011 06:43 PM |
| You wouldn't happen to know how to find the value of g prime of 1 when g is the inverse of the function f defined by f(x) = 2x^3 - 3/x would you? |
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| 22 Sep 2011 06:45 PM |
@Math
Nobody likes function notation. |
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sabricool
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Storm9802
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| 22 Sep 2011 06:47 PM |
x= -4
Im pretty sure
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sabricool
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Storm9802
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| 22 Sep 2011 06:51 PM |
@Sabri
Lets plug -3 into the equation and see it if works.
5*-3-1+7=3*-3
-15+7=-9
-8=/=-9
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Storm9802
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| 22 Sep 2011 06:52 PM |
Grah typo
-15+8 =-9
-7=/=-9
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| 22 Sep 2011 06:53 PM |
5(-3) - 1 + 7 = 3(-3) -15 - 1 + 7 = -9 -16 + 7 = -9 -9 = -9 |
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Chalklet
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Storm9802
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| 22 Sep 2011 06:55 PM |
The way I did it :P
OHHH NOW I SEE IT
I forgot a minus sign also means a negativvee
STUPID INTERNET
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