isseman6
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| Joined: 16 Feb 2016 |
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| 23 Apr 2017 02:54 PM |
A large 3.00×104 L aquarium is supported by four wood posts at the corners. Each post has a square 4.20 cm x 4.20 cm cross section and is 90.0 cm tall.
By how much is each post compressed by the weight of the aquarium?
solve it and make it clear to follow so i can understand
here is what i tried to do, volume of aquarium*density of water (1000) *gravity/ 0.042^2 *4
i got the wrong answer |
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| 23 Apr 2017 02:57 PM |
The resistance of the wood is needed
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isseman6
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| 23 Apr 2017 03:02 PM |
| (3 # #### # ### # ########### # 0.0104) |
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isseman6
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| Joined: 16 Feb 2016 |
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| 23 Apr 2017 03:08 PM |
if i am not mistaken
the mass of the aquarium is density of water * volume = 3.00*104L
so then area of one post is .051m*.051m=0.0026m^2
so then the total area of the post is 0.0026*4=0.0104
(3*10^4 * 9.8 * 0.9)/(10^10 * 0.0104)
you get 0.0025m
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isseman6
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| Joined: 16 Feb 2016 |
| Total Posts: 3224 |
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isseman6
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| Joined: 16 Feb 2016 |
| Total Posts: 3224 |
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isseman6
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| Joined: 16 Feb 2016 |
| Total Posts: 3224 |
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| 23 Apr 2017 06:21 PM |
@thelast
I already solved its 3.2 mm, I read up on young modulus and you came pretty close except you messed up with the area it should be (0.042)^2*4 |
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