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| 05 Apr 2017 01:59 PM |
| Four workers could do k jobs in m hours. At the same overall rate, how long would it take them to do 35 jobs? |
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| 05 Apr 2017 02:00 PM |
| Sorry, different problem, If 3 more workers were hired, how long would it take? |
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Lapidite
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| Joined: 19 May 2015 |
| Total Posts: 1415 |
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| 05 Apr 2017 02:01 PM |
but what's the rate?
nothing beats a jelly-filled doughnut |
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| 05 Apr 2017 02:02 PM |
then it shall be
k+v4+99-x-y=359867 hours to make 35 jobs
I used to be a egg (rap 0,001) |
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| 05 Apr 2017 02:03 PM |
| Was looking at the wrong problem so I mixed them, get rid of the overall average rate part and replace it with, 'if three more workers were hired'. |
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| 05 Apr 2017 02:05 PM |
| First we substitute 4 for w, k for j, and m for t. Then we solve for r. |
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| 05 Apr 2017 02:08 PM |
| We get k over 4m for r. Then we do the equation rwt=j again, thus time substituting k over 4m for r, 35 for j, and 7 for w, then solve for t. |
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omdaish
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| Joined: 18 Mar 2017 |
| Total Posts: 452 |
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| 05 Apr 2017 02:09 PM |
math wiz alert
ryan was kneeling in the bathtub |
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| 05 Apr 2017 02:10 PM |
| We get 20m over k hrs. Aren't abstract rate problems fun? |
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| 05 Apr 2017 02:11 PM |
| Jk, advanced mathematics are NOT fun. |
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