Jackudy3
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| Joined: 22 Sep 2011 |
| Total Posts: 8446 |
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| 23 Nov 2016 01:18 PM |
a = b a squared = ab a squared - b squared = ab-b squared (a-b)(a+b) = b(a-b) a+b = b b+b = b 2b = b 2 = 1 |
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Jackudy3
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| Joined: 22 Sep 2011 |
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Ornym
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| Joined: 14 Jan 2008 |
| Total Posts: 24266 |
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| 23 Nov 2016 01:23 PM |
this reminds me of the pythagorean theorem
though i was always terrible at math
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Jackudy3
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| Joined: 22 Sep 2011 |
| Total Posts: 8446 |
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| 23 Nov 2016 01:23 PM |
mathematicians c'mon prove this logic wrong
clearly 2 objects =/= 1 object |
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| 23 Nov 2016 01:24 PM |
| I'm on break please no math |
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Hunkeh
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| Joined: 05 Dec 2015 |
| Total Posts: 3080 |
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| 23 Nov 2016 01:25 PM |
That's not 2 = 1 that is
a = b a squared = ab a squared - b squared = ab-b squared (a-b)(a+b) = b(a-b) a+b = b b+b = b 2b = b 2 = 1 |
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Jackudy3
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| Joined: 22 Sep 2011 |
| Total Posts: 8446 |
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| 23 Nov 2016 01:26 PM |
@or
pythagoras' theorem is pretty easy
it's just used to find the length of the remaining side in a triangle given two other lengths, with the standard formula (c^2) = (a^2) + (b^2)
in english basically c is the hypotenuse (longest side of the triangle)
so with this information if you want to find the length of any remaining side you just shove the numbers into the equation and solve, working out the answer to each respective bracket and then square rooting |
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| 23 Nov 2016 01:27 PM |
I just woke up and I see this... T.T
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Jackudy3
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| Joined: 22 Sep 2011 |
| Total Posts: 8446 |
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| 23 Nov 2016 01:27 PM |
@laimon
that's exactly what i wrote lmao |
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| 23 Nov 2016 01:28 PM |
| but then 1 + 1 = 2 would be false if 2 is 1 |
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Jackudy3
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| Joined: 22 Sep 2011 |
| Total Posts: 8446 |
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| 23 Nov 2016 01:31 PM |
@penguin
yup, as i said here:
"mathematicians c'mon prove this logic wrong
clearly 2 objects =/= 1 object"
but prove it wrong mathematically |
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| 23 Nov 2016 01:32 PM |
if (a-b)(a+b) = b(a-b) if a=b doesn't a-b = 0? 0(a+b)=0 b(0)= 0 no?, lmao i just suck at math too. |
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Jackudy3
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| Joined: 22 Sep 2011 |
| Total Posts: 8446 |
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| 23 Nov 2016 01:34 PM |
"if a=b doesn't a-b = 0?"
yes, this works for negative numbers as well |
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| 23 Nov 2016 01:35 PM |
| @jack, so it's not 2=1 it's that equation=1 |
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Jackudy3
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| Joined: 22 Sep 2011 |
| Total Posts: 8446 |
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| 23 Nov 2016 01:38 PM |
@laimon
no, because look how i rearranged the equation to wind up with 2b = b
assuming b is 1, we're left with 2 = 1 if b was 2, we're left with 4 = 2 if b was 3, we're left with 6 = 3
and so on. |
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BuildersC
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| Joined: 19 Jul 2012 |
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| 23 Nov 2016 01:45 PM |
2 =/= 1 2^2 or 4 =/= 2(1) or 2 2^2 - 1^1 or 3 =/= 1(2)- 1 or 1 2-1(2+1) or 3 =/= 1(2-1) or 1 2+1 or 3 =/= 1 1+1 or 2 =/= 1 2(1) or 2 which is literally the same as the above =/= 1 2 =/= 1 |
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telnets
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| Joined: 10 May 2016 |
| Total Posts: 344 |
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| 23 Nov 2016 01:46 PM |
a=b a-b=0 cannot divide by zero
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JoshRBX
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| Joined: 19 May 2012 |
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| 23 Nov 2016 01:46 PM |
so you're saying b+b=b is the same as 2b=b
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telnets
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| Joined: 10 May 2016 |
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telnets
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| Joined: 10 May 2016 |
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| 23 Nov 2016 01:48 PM |
if a = b and a-b=0 then you cannot divide by zero in the 4th step
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| 23 Nov 2016 01:49 PM |
| jack, but that's not just 2=1, it's a reference with algebra which contradicts your point. |
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| 23 Nov 2016 01:50 PM |
uhh uhh uhh uhh
poop
2 = 1^2 |
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| 23 Nov 2016 01:50 PM |
| B is commonly refereed to 1B |
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