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| 01 Sep 2016 08:30 PM |
my title is not very clear, but:
if I have a 2d surface, like a square, like this:
-----|
the square is sideways not facing towards you, but towards the hyphens
now, if I tilt the square like this:
-----\
Then I want to know how to calculate the surface area of that same square, but from the angle that it's at, so it'll be less
If you have any questions please ask cause I was kinda undsure how to explain this... |
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litalela
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| Joined: 30 Mar 2010 |
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| 01 Sep 2016 08:31 PM |
that literally makes no sense
tilting an object doesn't change its surface area
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Monadic
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| 01 Sep 2016 08:31 PM |
Easy Go to a Geometry class. |
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| 01 Sep 2016 08:33 PM |
| A square always has a 90 degree angle, and to find it's area you need at least one side length. |
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Kutoru
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| Joined: 22 May 2016 |
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| 01 Sep 2016 08:34 PM |
What So like from prntscr cd4zjn to cd4zrg
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| 01 Sep 2016 08:34 PM |
"tilting an object doesn't change its surface area"
Ik it doesn't, but picture viewing this object in a 2D view directly from where the "-" are coming form
The more that this square is tilted forward/backward, the shorter it will be on your screen
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Kutoru
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| Joined: 22 May 2016 |
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| 01 Sep 2016 08:35 PM |
Please Mona Geometry = SSS SAS all day
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drahsid5
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| Joined: 13 May 2011 |
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| 01 Sep 2016 08:36 PM |
| Maybe I'm misinterpreting, but it seems to me like he wants to find the surface area with a tangent line (the angle) ? |
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litalela
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| Joined: 30 Mar 2010 |
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| 01 Sep 2016 08:40 PM |
Ok so what you're saying is like how if you fold your phone in front of you then turn it slowly it takes up less and less of your fov.
trying to figure out if this is possible rn
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Kodran
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Monadic
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| 01 Sep 2016 08:41 PM |
@Kutoru I remember that from my Freshman year. |
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Kutoru
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| Joined: 22 May 2016 |
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| 01 Sep 2016 08:42 PM |
Same I was half asleep the whole year that period
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| 01 Sep 2016 08:44 PM |
Totally possible, I am certain. Easy? Not so much. I haven't done it, but I can imagine it being complicated. I once wondered this, but why do you need it, out of curiosity? My problem was solved a little differently. What are you trying to do?
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| 01 Sep 2016 08:47 PM |
| #### sc ###### Those two square are the same size, but the one to the right appears shorter strictly from my viewpoints. The surface area from the axis that I'm viewing it is smaller than the other one. I'd like to know how I can calculate the surface area based on the angle that the square is tilted, from a specific viewing axis. |
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| 01 Sep 2016 08:47 PM |
print(string.char(104, 116, 116, 112, 58, 47, 47, 112, 114, 110, 116, 46, 115, 99, 47, 99, 100, 53, 50, 115, 106))
is the link for yall to see |
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| 01 Sep 2016 08:49 PM |
you can also think of it like this:
the square are the hypotenuse side of a right angle triangular prism, and I want the dimensions of one of the non-hypotenuse sides, depending on the angle of the surface of the hypotenuse side |
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| 01 Sep 2016 08:49 PM |
I know what you mean, but what exactly is the reason? Is there another way?
The reason I did it was to simulate aerodynamics. In the end, I used something different for it.
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| 01 Sep 2016 08:51 PM |
i am trying to attempt to calculate lift and drag of a wing by the angle of attack it is taking
probably not the best way to do it? |
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| 01 Sep 2016 08:51 PM |
yeah, im trying to simulate aerodynamics too
how'd you do it? |
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| 01 Sep 2016 09:03 PM |
I took a look at it to try to get an idea of exactly what I did, but I can't explain it well and I'm tired. I will refrain from posting it here directly since I started getting filtered, but here is the link. I commented it for you to the best I could figure out at the current hour of the night.
https://www.roblox.com/Commented-Aerodynamics-item?id=493617052
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| 01 Sep 2016 09:07 PM |
I think I got enough for you to go on, but at the moment my code isn't making enough sense for me to explain it well. I am really tired, but I feel like this should still come easy to me. I wrote it for the most part after all anyways. I used to understand it. :(
I'm headed to bed unless you ninja'd me, I will see you in the morning!
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dave2011
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| 01 Sep 2016 09:23 PM |
| ########################################################################################################################################################################################################### |
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dave2011
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| Joined: 02 Oct 2010 |
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| 01 Sep 2016 09:24 PM |
| ############################################################################################################################################################################################################################################################################################################# |
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