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Re: TRIANGLES!!!

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LateralLace is not online. LateralLace
Joined: 19 Sep 2015
Total Posts: 662
20 Aug 2016 11:41 PM
How would you split an isoleces triangle into right ones (wedges)? Geometry and trigonometry are screwing me over here.


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pullman45 is not online. pullman45
Joined: 09 Jul 2012
Total Posts: 2891
20 Aug 2016 11:42 PM
Split the triangle in halve.
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LateralLace is not online. LateralLace
Joined: 19 Sep 2015
Total Posts: 662
20 Aug 2016 11:43 PM
Woops meant scalene that rolled of my tongue harshly.


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pullman45 is not online. pullman45
Joined: 09 Jul 2012
Total Posts: 2891
20 Aug 2016 11:45 PM
Oh, uh...
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2eggnog is not online. 2eggnog
Joined: 08 Nov 2008
Total Posts: 1351
20 Aug 2016 11:46 PM
What information do you already have? Side lengths, angles, or points?


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LateralLace is not online. LateralLace
Joined: 19 Sep 2015
Total Posts: 662
20 Aug 2016 11:48 PM
Visualize a iso triangle, take one of it's bottom points and push it down one unit. Now what do I do?!?


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pullman45 is not online. pullman45
Joined: 09 Jul 2012
Total Posts: 2891
20 Aug 2016 11:48 PM
I think I know how wait.
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pullman45 is not online. pullman45
Joined: 09 Jul 2012
Total Posts: 2891
20 Aug 2016 11:52 PM
Did you mean scalene again?
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LateralLace is not online. LateralLace
Joined: 19 Sep 2015
Total Posts: 662
20 Aug 2016 11:53 PM
^^ *iso* meaning *isosoleces*


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pullman45 is not online. pullman45
Joined: 09 Jul 2012
Total Posts: 2891
20 Aug 2016 11:54 PM
Oh no you wait can't see the degrees of the triangle's angles right?
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SashimiRoll is not online. SashimiRoll
Joined: 24 Dec 2015
Total Posts: 72
20 Aug 2016 11:55 PM
Two articles on the wiki show how but you need the three vertices

http://wiki.roblox.com/index.php?title=3D_triangles
http://wiki.roblox.com/index.php?title=2D_triangles
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pullman45 is not online. pullman45
Joined: 09 Jul 2012
Total Posts: 2891
20 Aug 2016 11:55 PM
I just thought you meant scalene; at first you meant scalene but now an isosceles.
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2eggnog is not online. 2eggnog
Joined: 08 Nov 2008
Total Posts: 1351
20 Aug 2016 11:59 PM
Idk what you mean by that, but you can just use the Pythagorean theorem.

If you have sides with lengths 2, 3, 4, then you can set up a system of equations like this, with x being the distance from one of the vertices on the long side:
3^2 = x^2 + h^2
2^2 = (4-x)^2 + h^2
Which, despite having two variables, you can solve by subtracting the two and cancelling the h^2.


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LateralLace is not online. LateralLace
Joined: 19 Sep 2015
Total Posts: 662
21 Aug 2016 12:12 AM
http://prnt.sc/c8dxtv


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