generic image
Processing...
  • Games
  • Catalog
  • Develop
  • Robux
  • Search in Players
  • Search in Games
  • Search in Catalog
  • Search in Groups
  • Search in Library
  • Log In
  • Sign Up
  • Games
  • Catalog
  • Develop
  • Robux
   
ROBLOX Forum » Club Houses » ROBLOX Talk
Home Search
 

Re: hu giys

Previous Thread :: Next Thread 
quadrupledigitIQ is not online. quadrupledigitIQ
Joined: 27 May 2016
Total Posts: 4
28 May 2016 06:01 PM
o wsh rthat oroblosxwdipul;d mauhlelekwe gi ldlkfl v beuvhemtes


Report Abuse
iiFerexes is not online. iiFerexes
Joined: 17 Jul 2014
Total Posts: 8664
28 May 2016 06:03 PM
Ultimate unscramble
Report Abuse
quadrupledigitIQ is not online. quadrupledigitIQ
Joined: 27 May 2016
Total Posts: 4
28 May 2016 06:07 PM
>ultimate unscramble
One-half of √2, also the reciprocal of √2, approximately 0.707106781186548, is a common quantity in geometry and trigonometry because the unit vector that makes a 45° angle with the axes in a plane has the coordinates

\left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right).
This number satisfies

\tfrac{1}{2}\sqrt{2} = \sqrt{\tfrac{1}{2}} = \frac{1}{\sqrt{2}} = \cos 45^{\circ} = \sin 45^{\circ}.
One interesting property of √2 is as follows:

\!\ {1 \over {\sqrt{2} - 1}} = \sqrt{2} + 1
since

\left(\sqrt{2}+1\right)\left(\sqrt{2}-1\right)=2-1=1.
This is related to the property of silver ratios.

√2 can also be expressed in terms of the copies of the imaginary unit i using only the square root and arithmetic operations:

\frac{\sqrt{i}+i \sqrt{i}}{i}\text{ and }\frac{\sqrt{-i}-i \sqrt{-i}}{-i}
if the square root symbol is interpreted suitably for the complex numbers i and −i.

√2 is also the only real number other than 1 whose infinite tetrate (i.e., infinite exponential tower) is equal to its square. In other words: if for c > 1 we define x1 = c and xn+1 = cxn for n > 1, we will call the limit of xn as n → ∞ (if this limit exists) f(c). Then √2 is the only number c > 1 for which f(c) = c2. Or symbolically:

\sqrt{2}^ {(\sqrt{2}^ {(\sqrt{2}^ {(\ \cdot^ {\cdot^ \cdot)))}}}} = 2.
√2 appears in Viète's formula for π:

2^m\sqrt{2-\sqrt{2+\sqrt{2+\cdots+\sqrt{2}}}} \to \pi\text{ as }m \to \infty\,
for m square roots and only one minus sign.[19]

Similar in appearance but with a finite number of terms, √2 appears in various trigonometric constants:[20]

\sin(\pi/32) = \tfrac12\sqrt{2-\sqrt{2+\sqrt{2+\sqrt{2}}}};
\sin(\pi/16) = \tfrac12\sqrt{2-\sqrt{2+\sqrt{2}}};
\sin(3\pi/32) = \tfrac12\sqrt{2-\sqrt{2+\sqrt{2-\sqrt{2}}}};
\sin(\pi/8) = \tfrac12\sqrt{2-\sqrt{2}};
\sin(5\pi/32) = \tfrac12\sqrt{2-\sqrt{2-\sqrt{2-\sqrt{2}}}};
\sin(3\pi/16) = \tfrac12\sqrt{2-\sqrt{2-\sqrt{2}}};
\sin(7\pi/32) = \tfrac12\sqrt{2-\sqrt{2-\sqrt{2+\sqrt{2}}}};
\sin(\pi/4) = \tfrac12\sqrt{2};
\sin(9\pi/32) = \tfrac12\sqrt{2+\sqrt{2-\sqrt{2+\sqrt{2}}}};
\sin(5\pi/16) = \tfrac12\sqrt{2+\sqrt{2-\sqrt{2}}};
\sin(11\pi/32) = \tfrac12\sqrt{2+\sqrt{2-\sqrt{2-\sqrt{2}}}};
\sin(3\pi/8) = \tfrac12\sqrt{2+\sqrt{2}};
\sin(13\pi/32) = \tfrac12\sqrt{2+\sqrt{2+\sqrt{2-\sqrt{2}}}};
\sin(7\pi/16) = \tfrac12\sqrt{2+\sqrt{2+\sqrt{2}}};
\sin(15\pi/32) = \tfrac12\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{2}}}}.
It is not known whether √2 is a normal number, a stronger property than irrationality, but statistical analyses of its binary expansion are consistent with the hypothesis that it is normal to base two.[21]




Report Abuse
brpal is not online. brpal
Joined: 23 Jun 2011
Total Posts: 755
28 May 2016 06:08 PM
understandable


Report Abuse
Previous Thread :: Next Thread 
Page 1 of 1
 
 
ROBLOX Forum » Club Houses » ROBLOX Talk
   
 
   
  • About Us
  • Jobs
  • Blog
  • Parents
  • Help
  • Terms
  • Privacy

©2017 Roblox Corporation. Roblox, the Roblox logo, Robux, Bloxy, and Powering Imagination are among our registered and unregistered trademarks in the U.S. and other countries.



Progress
Starting Roblox...
Connecting to Players...
R R

Roblox is now loading. Get ready to play!

R R

You're moments away from getting into the game!

Click here for help

Check Remember my choice and click Launch Application in the dialog box above to join games faster in the future!

Gameplay sponsored by:
Loading 0% - Starting game...
Get more with Builders Club! Join Builders Club
Choose Your Avatar
I have an account
generic image