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| 23 Apr 2016 09:39 PM |
Step 1: Let a = b.
Step 2: Multiply a to each side. a^2 = ab
Step 3: Add a^2 to each side. a^2 + a^2 = a^2 + ab
Step 4: Simplify like terms. 2a^2 = a^2 + ab
Step 5: Subtract 2ab from each side. 2a^2 - 2ab = a^2 + ab - 2ab
Step 6: Simplify like terms. 2a^2 - 2ab = a^2 - ab
Step 7: Simplify. 2(a^2 - ab) = 1(a^2 - ab)
Step 8: Divide both sides by (a^2 - ab) 2 = 1 |
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| 23 Apr 2016 09:42 PM |
| Where did a squared come from |
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| 23 Apr 2016 09:45 PM |
See problems like these are the reasons why I fail math classes.
inb4mods |
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| 23 Apr 2016 09:46 PM |
| You would distribute the one and two, not divide them. |
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| 23 Apr 2016 09:54 PM |
@Limited
The 1 and the 2 are never divided. |
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| 23 Apr 2016 09:55 PM |
or you could just do 2-1 right |
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| 23 Apr 2016 09:56 PM |
that wouldnt be right tho if 2 = 1 then the equation is unsolvable
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| 23 Apr 2016 09:56 PM |
| You divided (a^2 - ab), I know how to math ok |
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| 23 Apr 2016 09:59 PM |
| Plus if the variable a equaled the variable b, that is a statement. We are not given any other information in the problem |
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| 23 Apr 2016 10:03 PM |
@Limited
You can do algebra with any statement whatsoever. You may not know what a and b equal, but 2a^2 - 2ab = a^2 + ab - 2ab is as true as a = b. In the original post I did some steps of algebra that suggested 2 = 1. Can you find what went wrong? |
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| 23 Apr 2016 10:07 PM |
@science
Obviously 2 can't equal 1, but what went wrong in the steps to get there? |
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| 23 Apr 2016 10:10 PM |
| So far no one has figured out what went wrong... |
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| 23 Apr 2016 10:12 PM |
I told you, you didn't distribute the 2 and 1.
2(a^2 - ab)= 1(a^2 - ab) distributive prop. 2a^2 - 2ab = a^2 - ab Now subtract a^2 a^2 - 2ab = - ab Now add ab a^2 - ab = 0 Now add ab again a^2 = ab Now take the square root of both sides
And it just gets you back to a = b, you need something to take the place of A or B to make it a problem |
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| 23 Apr 2016 10:15 PM |
wait so like for step 7 don't you use the distributive property
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| 23 Apr 2016 10:15 PM |
@Limited
Okay... try and forget going backwards in steps for a moment. Think what you get when you divide (a^2 - ab) to both side of 2(a^2 - ab)= 1(a^2 - ab). Algebraically, it's perfectly valid. But it gives you 2 = 1, why is that? |
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| 23 Apr 2016 10:19 PM |
| Listen here, algebra does not work like that. It is not valid. You are and will be wrong. There are so many sites that claim that they found it but are debunked. I hope you get some tutoring soon, you are a bit confused. |
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| 23 Apr 2016 10:20 PM |
I may as well give the answer now.
The problem is at step 8: dividing both sides by (a^2 - ab).
a^2 - ab can be simplified to a - b, and since a = b, a - b is zero.
We are dividing by 0 at step 8. |
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| 23 Apr 2016 10:21 PM |
@Limited
You sound frustrated. Maybe you should stick to your "solve for x" homework problems before leaping into more advanced problems like this. |
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| 23 Apr 2016 10:30 PM |
| u cant divide by 0 this is old tbh we even did this in my calc class |
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| 23 Apr 2016 10:31 PM |
| How clear do I have to be? Do you not know how the distributive property works? |
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| 23 Apr 2016 10:33 PM |
| AP CALC AB EXAM IS LESS THAN TWO WEEKS FROM NOW HELP |
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