God_Rod
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| Joined: 24 Feb 2016 |
| Total Posts: 714 |
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| 10 Apr 2016 10:17 PM |
| I got a quiz tomorrow (chemistry) |
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Holtbyism
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| Joined: 01 Feb 2013 |
| Total Posts: 2621 |
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| 10 Apr 2016 10:20 PM |
| Make sure you have the same number of moles for each element/compound on each side. Not hard at all. |
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God_Rod
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| Joined: 24 Feb 2016 |
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Diskerud
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| Joined: 17 Feb 2014 |
| Total Posts: 7395 |
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| 10 Apr 2016 10:24 PM |
| https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/balancing-chemical-equations/v/balancing-chemical-equations-introduction |
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Holtbyism
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| Joined: 01 Feb 2013 |
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| 10 Apr 2016 10:25 PM |
2H2O + 3Mg = H2O + Mg
Add a 2 in front of the H20 and add a 3 to the Mg |
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God_Rod
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| Joined: 24 Feb 2016 |
| Total Posts: 714 |
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| 10 Apr 2016 10:27 PM |
So if it's
AI + O2 = AI2 + O3
Would I add 2 to the first one and 3 to the second one (O2)? |
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| 10 Apr 2016 10:27 PM |
Compare the two sides of each equation, break it down to it's elements (Element examples: C, O, Na, K, P, Hg, the stuff you see on a periodic table)
Count the number of each element you see on each side. For example, you might see Cl2 (the 2 is a subscript), that's 2 Cl's, easy. For something like Ca(OH)2, that's a bit harder. There is 1 Ca element, 2 O's, and 2 H's in that situation.
Use coefficients to balance the equations.
For example:
http://woodridge.k12.oh.us/ourpages/users/dweaver/Chemistry/ChemistryHelpTopics/BalancingEquations/eqn1.jpg
Any questions lmk |
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| 10 Apr 2016 10:30 PM |
AI + O2 = AI2 + O3
If you mean Al instead of AI (for Aluminum), then
Left side: 1 Al, 2 O's Right side: 2 Al's, 3 O's
Now use coefficients to multiply.
2Al + O2 = Al2 + O3 Left side: 2 Al's, 2 O's Right side: 2 Al's, 3 O's
2Al + 3O2 = Al2 + O3 Left side: 2 Al's, 6 O's Right side: 2 Al's, 2 O's
2Al + 3O2 = Al2 + 2O3 Left side: 2 Al's, 6 O's Right side: 2 Al's, 6 O's
***You are allowed to add any coefficient to any molecule/element you see. |
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God_Rod
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| Joined: 24 Feb 2016 |
| Total Posts: 714 |
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Holtbyism
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| Joined: 01 Feb 2013 |
| Total Posts: 2621 |
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| 10 Apr 2016 10:35 PM |
| Your primary objective is to have the same number of moles on each side. It's simple |
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God_Rod
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| Joined: 24 Feb 2016 |
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| 10 Apr 2016 10:39 PM |
| Watch this and you'll be set: https://www.youtube.com/watch?v=RnGu3xO2h74 |
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Holtbyism
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| Joined: 01 Feb 2013 |
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| 10 Apr 2016 10:40 PM |
You want to multiply them till they equal basically.
AI + O2 = AI2 + O3
AI times two to get them equal.
You want O2 and O3 to be equal so you find the first number both of them can be.
Multiply the O2 by 3 to get O6
Multiply the O3 by 2 to get O6
Answer: AI2 + O6 = AI2 + O6 |
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| 10 Apr 2016 10:45 PM |
Here's a practice problem I came up with for you:
Na3 + Mg4 = Na2+ Mg8
Remember you want to multiply till they equal each other. |
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| 10 Apr 2016 10:46 PM |
"Na3 + Mg4 = Na2+ Mg8"
doesn't the number go in front |
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God_Rod
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| Joined: 24 Feb 2016 |
| Total Posts: 714 |
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| 10 Apr 2016 10:47 PM |
| I think I get it now, not sure, hopefully I'll pass my quiz thanks guys :) |
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| 10 Apr 2016 10:48 PM |
Yes, Ano. I'm following his format if the teacher expects it that way.
I do it infront though. |
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| 10 Apr 2016 10:48 PM |
| if its at the end it looks like polyatomic |
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God_Rod
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| Joined: 24 Feb 2016 |
| Total Posts: 714 |
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| 10 Apr 2016 10:49 PM |
"Na3 + Mg4 = Na2+ Mg8"
Na6 + Mg32 = Na6 + Mg32? |
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| 10 Apr 2016 10:51 PM |
Yes on Na.
No on Mg.
4 can be multipled by 2 to equal 8.
Mg8 you just multiply by 1
Answer: Na6 + Mg8 = Na6 + Mg8 |
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God_Rod
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| Joined: 24 Feb 2016 |
| Total Posts: 714 |
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| 10 Apr 2016 10:52 PM |
| Give me another one please |
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| 10 Apr 2016 10:53 PM |
Here's another random one I thought of:
Hg5 + C8 = Hg15 + C2 |
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