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| 08 Feb 2016 08:47 AM |
| i know it seems like 6th grade stuff but i tried and i don't get it |
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hobosrule
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| Joined: 12 Dec 2008 |
| Total Posts: 1960 |
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| 08 Feb 2016 08:51 AM |
| i think u have to use a formula |
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| 08 Feb 2016 08:58 AM |
x=3y-9
The formula is y=mx+b
The +b is the y-intercept. Yours is -9 so on the the y-axis, plot a point at (0, -9) m is the slope. Since yours is 3, at your first point, move up three boxes, then right 1 box and plot a point. Then do it again so up another 3 and over 1. And stop when you can clearly see the line. |
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| 08 Feb 2016 08:58 AM |
| i'll give you the answers but I can't be bothered to write how to do it |
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| 08 Feb 2016 08:59 AM |
@punish the problem is the graphing part because the only points that intercept are at (0,0) and it has to intercept somewhere else but it's nkt |
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| 08 Feb 2016 09:02 AM |
Are both of the two you posted on the same graph?
The one I said does not intercept (0, 0).
The +b decides where it intercepts the y-axis so because its not just y=mx it has it bit somewhere other than (0, 0) |
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