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| 27 Jan 2016 12:01 PM |
so lets say u have two prime numbers that are greater than 4 and the difference between them is two
for exmaple 11 and 13 the number in between them will always be a multiple of six!!
prove it!
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| 27 Jan 2016 12:02 PM |
1+1=2 did i win?
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HeilHalie
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L2000
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| 27 Jan 2016 12:03 PM |
Potato.
insert gooiness here
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Whippetss
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| 27 Jan 2016 12:04 PM |
11 + 13 is 24 multiple of 6 59 + 61 is 120 multiple of 6???
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| 27 Jan 2016 12:05 PM |
@whip wut have u proved m8
bump!!
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Terran87
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| 27 Jan 2016 12:08 PM |
Its false
23, 29
Median in between is 26
26 / 6 =/= whole number |
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Terran87
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| 27 Jan 2016 12:08 PM |
on the difference is two nvm 1 sec |
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polfy99
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| 27 Jan 2016 12:10 PM |
bump
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| 27 Jan 2016 12:11 PM |
@polfy
did i not say for prime numbers greater than 4
to my knawlidge, 3 is not greater than 4
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Terran87
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| 27 Jan 2016 12:15 PM |
11,13 , 11+13/2 = 12
12 is a multiple of 6 i gues/.!?!?! |
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| 27 Jan 2016 12:15 PM |
bump!!
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polfy99
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| 27 Jan 2016 12:15 PM |
yes terran but now prove it for all prime numbers whose difference is two( such that the prime numbers are greater than 4)
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Terran87
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| 27 Jan 2016 12:20 PM |
wut r u saying is a fact
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Terran87
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dag98
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| 27 Jan 2016 12:21 PM |
3 and 5 = 4 4/6=/=whole number |
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| 27 Jan 2016 12:22 PM |
@dag
3 is not greater than 4
i will show u guys the proof when the 2nd page starts
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| 27 Jan 2016 12:23 PM |
bump
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| 27 Jan 2016 12:24 PM |
!!!
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Terran87
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| 27 Jan 2016 12:27 PM |
6q - 1 + 2 = 6q + 1
Let's say you have 2 prime numbers, and their difference is two. The middle number divided by 6, when plugged into the equation, will always give you the higher prime number of the two.
6q - 1 will always give you the lower prime number of the set. 6q + 1 will always give you the higher prime number.
But if you do 6q - 1 + 2 then if the result is equal to 6q + 1 , then the number of equivalence is always the higher prime number that satisfies this.
did i do it!
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| 27 Jan 2016 12:27 PM |
fine hes the proof
the two primes greater than 4 have to be odd correct yes we know that
so the number in between has to be even
and then lets say the first prime is p1 and the second is p2
p2 - 3 = p1 - 1
p2-3 is not divisible by 3 because p2 is not
so u have p2-3, p1, and then the number in between
the number in between has to be disivible by 3 because the two numbers that come before it arent
so since the number in between is disivible by both 2 and 3 it must be disivible by 6
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| 27 Jan 2016 12:30 PM |
terran
that works but first u have to prove why 6q + 1 and 6q -1 will be prime
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