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Re: a math challenge EDIT for lmads! yay!!

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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:01 PM
so lets say u have two prime numbers that are greater than 4
and the difference between them is two

for exmaple 11 and 13
the number in between them will always be a multiple of six!!

prove it!


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ContentClassic is not online. ContentClassic
Joined: 03 Jan 2016
Total Posts: 15800
27 Jan 2016 12:02 PM
1+1=2
did i win?


Send me offers please 🐰 http://www.roblox.com/Trade/TradeWindow.aspx?TradePartnerID=19980681 Rs: 12,437 | Tix: 3,620 *ADD 7K TO POST COUNT
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HeilHalie is not online. HeilHalie
Joined: 11 Sep 2012
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27 Jan 2016 12:02 PM
potato


call me leighton 💕
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L2000 is not online. L2000
Joined: 03 Apr 2008
Total Posts: 77448
27 Jan 2016 12:03 PM
Potato.

insert gooiness here



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Whippetss is not online. Whippetss
Joined: 09 Dec 2015
Total Posts: 1015
27 Jan 2016 12:04 PM
11 + 13 is 24 multiple of 6
59 + 61 is 120 multiple of 6???



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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:05 PM
@whip
wut have u proved m8

bump!!

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Terran87 is not online. Terran87
Joined: 23 Jan 2016
Total Posts: 713
27 Jan 2016 12:08 PM
Its false

23, 29

Median in between is 26

26 / 6 =/= whole number
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Terran87 is not online. Terran87
Joined: 23 Jan 2016
Total Posts: 713
27 Jan 2016 12:08 PM
on the difference is two
nvm 1 sec
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polfy99 is not online. polfy99
Joined: 06 Nov 2009
Total Posts: 60270
27 Jan 2016 12:10 PM
3,5
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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:10 PM
bump

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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:11 PM
@polfy

did i not say for prime numbers greater than 4

to my knawlidge, 3 is not greater than 4

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Terran87 is not online. Terran87
Joined: 23 Jan 2016
Total Posts: 713
27 Jan 2016 12:15 PM
11,13 , 11+13/2 = 12

12 is a multiple of 6 i gues/.!?!?!
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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:15 PM
bump!!

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polfy99 is not online. polfy99
Joined: 06 Nov 2009
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27 Jan 2016 12:15 PM
o
k


















o


















k
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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:15 PM
yes terran but now prove it for all prime numbers whose difference is two( such that the prime numbers are greater than 4)

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Terran87 is not online. Terran87
Joined: 23 Jan 2016
Total Posts: 713
27 Jan 2016 12:19 PM
is it a fact though
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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:20 PM
wut r u saying is a fact

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Terran87 is not online. Terran87
Joined: 23 Jan 2016
Total Posts: 713
27 Jan 2016 12:20 PM
x = 6y + b?
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dag98 is not online. dag98
Joined: 12 Jan 2008
Total Posts: 11558
27 Jan 2016 12:21 PM
3 and 5 = 4
4/6=/=whole number
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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:22 PM
@dag

3 is not greater than 4

i will show u guys the proof when the 2nd page starts

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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
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27 Jan 2016 12:23 PM
bump

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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:24 PM
!!!

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Terran87 is not online. Terran87
Joined: 23 Jan 2016
Total Posts: 713
27 Jan 2016 12:27 PM
6q - 1 + 2 = 6q + 1

Let's say you have 2 prime numbers, and their difference is two.
The middle number divided by 6, when plugged into the equation, will always give you the higher prime number of the two.

6q - 1 will always give you the lower prime number of the set.
6q + 1 will always give you the higher prime number.

But if you do 6q - 1 + 2 then if the result is equal to 6q + 1 , then the number of equivalence is always the higher prime number that satisfies this.



did i do it!


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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:27 PM
fine hes the proof

the two primes greater than 4 have to be odd correct yes we know that

so the number in between has to be even

and then lets say the first prime is p1 and the second is p2

p2 - 3 = p1 - 1

p2-3 is not divisible by 3 because p2 is not

so u have p2-3, p1, and then the number in between

the number in between has to be disivible by 3 because the two numbers that come before it arent

so since the number in between is disivible by both 2 and 3 it must be disivible by 6

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Coinman001 is not online. Coinman001
Joined: 10 Apr 2012
Total Posts: 56149
27 Jan 2016 12:30 PM
terran

that works but first u have to prove why 6q + 1 and 6q -1 will be prime

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