waysideme
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| Joined: 19 Dec 2009 |
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| 16 Aug 2015 08:03 PM |
You have a 5 gallon bucket filled with 2.5 gallons of water. In each gallon of water there are 3 grams of salt dissolved. You drain the bucket at a rate of 1/10th of a gallon per second. at the same time you fill the bucket with water that has 10 grams of salt dissolved in it per gallon at a rate of 1/5 gallons per second. When the bucket starts to overfill what is the concentration of salt inside the bucket?
CAN'T SOLVE HELP! |
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waysideme
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| Joined: 19 Dec 2009 |
| Total Posts: 3591 |
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| 16 Aug 2015 08:05 PM |
| I'll give the brightest minds of C&G some time to solve this question. |
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sterkte
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| Joined: 01 Jul 2013 |
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Proscate
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| Joined: 25 Jan 2013 |
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| 16 Aug 2015 08:07 PM |
| the problem is the concentration of the solution of salt leaving the bucket is constantly changing... |
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Arvoria
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| Joined: 13 Apr 2011 |
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| 16 Aug 2015 08:08 PM |
| feints bc of math question |
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waysideme
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| Joined: 19 Dec 2009 |
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| 16 Aug 2015 08:10 PM |
| still i can not answer question and it is not 50 i kno for a fact |
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Arvoria
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| Joined: 13 Apr 2011 |
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| 16 Aug 2015 08:13 PM |
5 gallon bucket already filled 1/2 of the way
you can forget about the 3 grams of salt dissolved altogether because...
drain 1/10 per second fill 2/10 per second
it will take 25 seconds in order to fill it to 5 gallons because... 25 seconds of drain = -2.5 gallons 25 seconds of fill = +5 gallons
2.5 - 2.5 + 5 = 5
so basically you're just filling an empty bucket with 5 gallons of water that has a concentration of 10g of salt per gallon and it will take 25 seconds to fill at a rate of 2/10 gallons per second
so.... 5 gallons of water with 10g of salt per gallon = 5 x 10 = 50g of salt
tada |
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waysideme
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| Joined: 19 Dec 2009 |
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Arvoria
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| Joined: 13 Apr 2011 |
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| 16 Aug 2015 08:15 PM |
Arvoria... *sigh*.
you cant forget the 3 grams of salt per gallon... when you pour the 10g of salt per gallon per second it mixes with the water already there, so when it drains the concentration of the water being drained is constantly changing. It doesn't drain out constantly at 3g per gallon |
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waysideme
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| Joined: 19 Dec 2009 |
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| 16 Aug 2015 08:15 PM |
| ur completely excluding the the first 3grams of salt dissolved per gallon. AND THAT IS WHAT MAKES IT SO HARD |
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Arvoria
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| Joined: 13 Apr 2011 |
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| 16 Aug 2015 08:16 PM |
yes but the idiots who make these questions dont think about that
im right |
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Arvoria
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| Joined: 13 Apr 2011 |
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| 16 Aug 2015 08:16 PM |
| hold on- wayside, what math course are you taking? |
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| 16 Aug 2015 08:16 PM |
| no they do think about it, that's the whole dam point of the question mg |
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waysideme
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| Joined: 19 Dec 2009 |
| Total Posts: 3591 |
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| 16 Aug 2015 08:18 PM |
| Advanced algebra and trigonometry |
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| 16 Aug 2015 08:18 PM |
| Honest to god I tried to solve this problem for an hour straight. F this I'm done |
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waysideme
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| Joined: 19 Dec 2009 |
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| 16 Aug 2015 08:20 PM |
| Any c&gerz who know some stuff about math want to help me outttt? |
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| 16 Aug 2015 08:20 PM |
This is a VERY easy question.
521 AM where I am ATM (vacation) will do it first thing In the morning. |
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| 16 Aug 2015 08:21 PM |
learned about this in chemistry
there's a formula look it up |
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Qiaolian
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| Joined: 22 Nov 2014 |
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| 16 Aug 2015 08:22 PM |
5 gallon bucket. 2.5 gallons of water. Each gallon being decreased is 3 grams of salt.
You're pouring 10 grams of salt per gallon into it at 1/5 gallons per second.
Every second: - 1/10 of original water + 1/5 of new water
After 10 seconds you'll lose 1 gallon of the original water content, and it will be replaced by 2 gallons of the new water content. The concentration quota will be 1.5 gallons of 3 grams salt dissolved + 2 gallons 10 grams salt dissolved. We can take the average to determine grams of salt dissolved later.
After 20 seconds, you'll lose 1 more gallon of original water, and 1 gallon of new water. 0.5 gallons 3 grams salt dissolved 4 gallons 10 salt dissolved.
Drain for 5 more seconds.
0 gallons 3 grams salt dissolved. 5 gallons 10 salt dissolved.
It'll end up overfilling when the time passes 25 seconds with a salt concentration of 10 grams per gallon.
Qiaolian/Centurians | RSTF train! #REXHYPE |
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waysideme
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| Joined: 19 Dec 2009 |
| Total Posts: 3591 |
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| 16 Aug 2015 08:22 PM |
| No anti u just dont know how to u it u BS'er |
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Qiaolian
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| Joined: 22 Nov 2014 |
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| 16 Aug 2015 08:22 PM |
you'll lose 1 more gallon of original water, and gain 2 gallons of new water***
Qiaolian/Centurians | RSTF train! #REXHYPE |
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