lucky908
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| Joined: 01 May 2011 |
| Total Posts: 1137 |
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| 17 May 2015 06:44 AM |
Let me go first...
What is x if 9x+5-3=37? (Pretty easy)
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Porks
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| Joined: 19 Sep 2012 |
| Total Posts: 1504 |
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| 17 May 2015 07:02 AM |
"What is x if 9x+5-3=37?"
9x + 5 - 3 = 37 <=> 9x = 37 - 5 + 3 <=> 9x = 35 <=> x = 35/9 = 3 + 8/9
Now for something a bit harder:
5 + 2cos(x + 0.25π) = 7
solve eit
"Go to hell, Aard" ~b0ddyp3n | Aard's alt, add 10k posts |
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redlego98
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| Joined: 11 Jul 2008 |
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| 17 May 2015 07:14 AM |
5 + 2cos(x + 0.25π) = 7 2 cos (x+ 0.25π) = 2 cos(x+ 0.25π) = 1 x+ 0.25π = 0 x = - 0.25π
Here is an easy one if you know what you are doing.
h(x) = {-2x² + 5x +10 for -4 ≤ x < 3 } {2x + 3p for 3 ≤ x ≤ 5 }
For what value of p will the function be continuous?
My name is Michael J. Caboose, and I hate babies! |
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Porks
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| Joined: 19 Sep 2012 |
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| 17 May 2015 08:07 AM |
"5 + 2cos(x + 0.25π) = 7 2 cos (x+ 0.25π) = 2 cos(x+ 0.25π) = 1 x+ 0.25π = 0 x = - 0.25π"
Nope.
You went wrong at the fourth line. It should be:
cos(x + 0.25π) = 1 <=> x + 0.25π = k * 2π <=> x = -0.25π + k * 2π
Remember that the cosine function is a wave and therefore it keeps... well... waving.
"Go to hell, Aard" ~b0ddyp3n | Aard's alt, add 10k posts |
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redlego98
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| Joined: 11 Jul 2008 |
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| 17 May 2015 02:16 PM |
Are you sure? I had plugged my answer in and I got 7.
My name is Michael J. Caboose, and I hate babies! |
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| 17 May 2015 02:18 PM |
| is this algebra 2 cuz ive never seen cosine in an equation/expression |
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0leeoX
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| Joined: 03 Apr 2015 |
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redlego98
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| Joined: 11 Jul 2008 |
| Total Posts: 8870 |
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| 17 May 2015 02:21 PM |
5 + 2cos(x + 0.25π) = 7 5 + 2cos(-0.25π+0.25π) = 7 5 + 2 cos (0) = 7 5 + 2*1 = 7 7 = 7
Just proof of concept.
My name is Michael J. Caboose, and I hate babies! |
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| 17 May 2015 02:22 PM |
| stop remembering i have school tomorrow |
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redlego98
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| Joined: 11 Jul 2008 |
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| 17 May 2015 02:24 PM |
It is Algebra 2, yes. That or pre-calc.
My name is Michael J. Caboose, and I hate babies! |
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