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| 21 Jan 2015 09:01 PM |
| or maybe i did really well |
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lion9031
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| Joined: 27 Jan 2011 |
| Total Posts: 14344 |
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| 21 Jan 2015 09:02 PM |
| I can't imagine how bad 12th grade math must be |
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Kokuen
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| Joined: 13 Apr 2012 |
| Total Posts: 7403 |
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| 21 Jan 2015 09:02 PM |
wow is 4th grade too hard
be a dragon |
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drakeh
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| Joined: 08 Sep 2008 |
| Total Posts: 7726 |
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| 21 Jan 2015 09:03 PM |
lowest grade on a test i ever got was a 42 oooh 7th grade
lets all have another orange julius |
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| 21 Jan 2015 09:03 PM |
"I can't imagine how bad 12th grade math must be"
not even 12th grade math, it's a math course from a college here. trying to get some freshman credits out of the way
it was hard |
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| 21 Jan 2015 09:03 PM |
"wow is 4th grade too hard"
Genius |
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IValerian
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| Joined: 01 May 2013 |
| Total Posts: 1588 |
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Kokuen
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| Joined: 13 Apr 2012 |
| Total Posts: 7403 |
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| 21 Jan 2015 09:04 PM |
honestly str8 a's aren't hard to get u know
be a dragon |
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| 21 Jan 2015 09:05 PM |
"wow is 4th grade too hard"
solve these
if f(x) = 1/x then f(a+h) = 1/a + 1/h
Let f(x) = 1/x. Obtain the expression for (f(a+h) - f(a))/h and simplify
If you can't solve these then you're the dumb 4th grader |
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| 21 Jan 2015 09:06 PM |
"if f(x) = 1/x then f(a+h) = 1/a + 1/h"
also this is a true/false question and work must be shown |
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| 21 Jan 2015 09:07 PM |
That's math IF that had else it would be a damn computer program |
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Boeing717
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| Joined: 08 Jun 2008 |
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| 21 Jan 2015 09:08 PM |
[f(x+h)-f(x)]/h = -1/(x^2) parentheses for more clarity, not for necessity |
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Ouendan
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| Joined: 20 Dec 2013 |
| Total Posts: 30191 |
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| 21 Jan 2015 09:08 PM |
| Zapping achievers get all the praise |
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zacmaq
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| Joined: 13 Jan 2013 |
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| 21 Jan 2015 09:09 PM |
if f(x) = 1/x then f(a+h) = 1/a + 1/h
Let f(x) = 1/x. Obtain the expression for (f(a+h) - f(a))/h and simplify
(1/a + 1/h - 1/a)/h
1/h/h=1 |
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Boeing717
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| Joined: 08 Jun 2008 |
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| 21 Jan 2015 09:09 PM |
""if f(x) = 1/x then f(a+h) = 1/a + 1/h"
also this is a true/false question and work must be shown"
its false
if f(x) = 1/x then f(a+h) = 1/(a+h) however 1/a + 1/h = (a+h)/(ah) |
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| 21 Jan 2015 09:10 PM |
"its false
if f(x) = 1/x then f(a+h) = 1/(a+h) however 1/a + 1/h = (a+h)/(ah)"
boeing is correct |
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zacmaq
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| Joined: 13 Jan 2013 |
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| 21 Jan 2015 09:11 PM |
"[f(x+h)-f(x)]/h = -1/(x^2)"
Screw yo vertex formula, I'm enjoying my done-with-calc privilege
4 ∫ x^3-(6/3)x^2-24x 3 |
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Boeing717
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| 21 Jan 2015 09:11 PM |
also is that second question supposed to be the limit as h approaches 0? because that's how i solved it |
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quinn04
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| Joined: 07 Jul 2011 |
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zacmaq
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| Joined: 13 Jan 2013 |
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| 21 Jan 2015 09:12 PM |
"boeing is correct"
I thought you typed a problem and didn't look to see if it was based wrong or whatever
Screw boeing |
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| 21 Jan 2015 09:12 PM |
"also is that second question supposed to be the limit as h approaches 0?"
you just need to simplify the equation
here's the start:
[(1/a+h) - (1/a)]/h |
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Kokuen
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| Joined: 13 Apr 2012 |
| Total Posts: 7403 |
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| 21 Jan 2015 09:12 PM |
no if i can't solve those i'm a grade below u lol
be a dragon |
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Kokuen
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| Joined: 13 Apr 2012 |
| Total Posts: 7403 |
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| 21 Jan 2015 09:13 PM |
no need honestly i wouldn't be a 4th grader i know you got these from your sister/dad/mom's workbook it doesn't take an einstein to know that
be a dragon |
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