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Re: Guys I DON'T get linear equations!

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Merriness is not online. Merriness
Joined: 05 Dec 2012
Total Posts: 7495
14 Dec 2014 09:17 PM
Unit test Wednesday! What to do? I've been practicing all day but no success.


~Mɛʀʀɨռɛֆֆ
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xSoulZy is not online. xSoulZy
Joined: 05 Apr 2010
Total Posts: 3520
14 Dec 2014 09:21 PM
Linear is simple

Linear doesn't pass by 0, it starts at a certain point.
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curve8900 is not online. curve8900
Joined: 23 May 2009
Total Posts: 4401
14 Dec 2014 09:21 PM
ok give me a quesiton

and ill answer it w/ full explanation
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Merriness is not online. Merriness
Joined: 05 Dec 2012
Total Posts: 7495
14 Dec 2014 09:23 PM
Alright Curve!

1 + 3/4 x > 17


~Mɛʀʀɨռɛֆֆ
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Merriness is not online. Merriness
Joined: 05 Dec 2012
Total Posts: 7495
14 Dec 2014 09:24 PM
Nvm that's an easy one

3/4 x > 16

x = 16 divided by 3/4


~Mɛʀʀɨռɛֆֆ
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Everment is not online. Everment
Joined: 08 Oct 2009
Total Posts: 6020
14 Dec 2014 09:25 PM
"1 + 3/4 x > 17"

Easy, multiply x by 3/4 (aka multiply by three then divide by 4) and add one. From there you only shade graph if that number is greater than (not at least) 17.

Anyway, what don't you understand about linear equations?
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Merriness is not online. Merriness
Joined: 05 Dec 2012
Total Posts: 7495
14 Dec 2014 09:25 PM
3/5 f - 1/2 < 2 + f


~Mɛʀʀɨռɛֆֆ
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curve8900 is not online. curve8900
Joined: 23 May 2009
Total Posts: 4401
14 Dec 2014 09:25 PM
1 + 0.75x > 17

subtract 1, you are trying to keep X alone

0.75x > 16

Divide each side by 0.75, because you need the X alone


x > ( 16 / .75)


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Merriness is not online. Merriness
Joined: 05 Dec 2012
Total Posts: 7495
14 Dec 2014 09:26 PM
I don't know when to subtract / divide / add / multiply sometimes.


~Mɛʀʀɨռɛֆֆ
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Widths is not online. Widths
Joined: 12 Aug 2014
Total Posts: 41286
14 Dec 2014 09:27 PM
R u 12


~winpo1 le august 2014 lmader master race :^)
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curve8900 is not online. curve8900
Joined: 23 May 2009
Total Posts: 4401
14 Dec 2014 09:27 PM
3/5 f - 1/2 < 2 + f

What I'd do first is subtract 3/5 F from both sides, making it


-1/2 < 2+ 2/5f


subtract 2


-2.5 < 2/5F


multiply each side by 5/2

-6.25 < F
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Everment is not online. Everment
Joined: 08 Oct 2009
Total Posts: 6020
14 Dec 2014 09:28 PM
3/5 f - 1/2 < 2 + f
-f
-2/5f - 1/2 < 2
+1/2
-2/5f < 5/2
*5
-2f < 25/2
/-2
f > -25/4 (note: the sign changed because you divided/multiplied by a negative)
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weinmanj is not online. weinmanj
Top 25 Poster
Joined: 24 May 2008
Total Posts: 59999
14 Dec 2014 09:28 PM
3/5 f - 1/2 < 2 + f
move the variables and numbers to one side

3/5f - f < 2 + 1/2

-0.4f < 2.5
divide by -0.4 and flip the inequality sign

f > -6.25
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curve8900 is not online. curve8900
Joined: 23 May 2009
Total Posts: 4401
14 Dec 2014 09:29 PM
wein weak

i did it first

i win u lose
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Everment is not online. Everment
Joined: 08 Oct 2009
Total Posts: 6020
14 Dec 2014 09:29 PM
curve: your sign is backwards, I even consulted wolfram alpha to make sure I wasn't doing something wrong.
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LethaIity is not online. LethaIity
Joined: 27 Oct 2013
Total Posts: 4060
14 Dec 2014 09:29 PM
3/5 f - 1/2 < 2 + f
gonna use decimals because its easier on a computer

0.6f - 0.5 < 2 + f

0.6f < 2.5 + f (You start by adding 0.5, the number, to isolate the variable.)

-0.4f < 2.5 (Subtract the f to consolidate all of the variables into one.)

f > -6.25 (Divide by -0.4 on both sides to isolate the variable, f, as just a variable, as in, without an integer with it. You turn the < into > because you're dividing by a negative integer.)

~ Vesp is NFT/NFS ~
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weinmanj is not online. weinmanj
Top 25 Poster
Joined: 24 May 2008
Total Posts: 59999
14 Dec 2014 09:30 PM
ok i was trying 2 format it
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Merriness is not online. Merriness
Joined: 05 Dec 2012
Total Posts: 7495
14 Dec 2014 09:30 PM
Thanks guys! :D

Widths, I'm 14 and am learning linear equations just this year in 9th grade.


~Mɛʀʀɨռɛֆֆ
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curve8900 is not online. curve8900
Joined: 23 May 2009
Total Posts: 4401
14 Dec 2014 09:30 PM
@ever

r u 12


-6.25 < F

is the same as

f > -6.25 ( which is how urs is formatted )

u also over complicated it so um

i win u loose
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Everment is not online. Everment
Joined: 08 Oct 2009
Total Posts: 6020
14 Dec 2014 09:31 PM
I'm in secondary I honors because I didn't want to take tests over the summer and I've already finished the whole year's worth of material.

I'm pretty sure I did this in 8th grade anyway.
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weinmanj is not online. weinmanj
Top 25 Poster
Joined: 24 May 2008
Total Posts: 59999
14 Dec 2014 09:31 PM
"linear equations just this year in 9th grade."

what
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Everment is not online. Everment
Joined: 08 Oct 2009
Total Posts: 6020
14 Dec 2014 09:31 PM
curve: derp I thought yours was facing the same way mine was (aka yours was >)

I can't read I should leave
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curve8900 is not online. curve8900
Joined: 23 May 2009
Total Posts: 4401
14 Dec 2014 09:32 PM
well read my post again cuz u must have made a mistake

both our answers are the same exact thing
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Everment is not online. Everment
Joined: 08 Oct 2009
Total Posts: 6020
14 Dec 2014 09:32 PM
I noticed, hence the fact that I pointed out my mistake
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curve8900 is not online. curve8900
Joined: 23 May 2009
Total Posts: 4401
14 Dec 2014 09:32 PM
late post

sry m8
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