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| 07 Sep 2014 09:40 PM |
Given A(1,2k) and B(2k+1,5) two points on line l. Determine the value of parameter k if:
The slope of l is equal to 3/2 (3 over 2)
please explan how to do this. |
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Kasurokov
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| Joined: 12 Jan 2012 |
| Total Posts: 9215 |
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| 07 Sep 2014 09:49 PM |
| you ask c&g rather than searching this up on google |
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| 07 Sep 2014 09:50 PM |
kasurokov, why dont you tell me what the hell i search in google to get the answer to this obscure question
"analytic geometry examples" give me much different questions
especially because this is a canadian curriculum-based book |
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The96
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| Joined: 29 Jul 2013 |
| Total Posts: 267 |
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| 07 Sep 2014 09:51 PM |
draw a picture of a graph set up an equation from it 5-2k = 2k+1-1 solve for k |
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| 07 Sep 2014 09:51 PM |
| I would help but I got math homework of my own to do... |
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| 07 Sep 2014 09:51 PM |
POINT SLOPE FORM (SIMPLIFIED) IS m = y-y1/x-x1 WHERE M = THE SLOPE.
SUBSTITUTE
A(1, 2k) and B(2K+1, 5), M IS 3/2
3/2 = 5 - 2K / 2K+1 - 1
CROSS MULTIPLY
3(2K) = 2(5 - 2K)
SOLVE FOR K
6K = 10 - 4K
10K = 10
K = 1
YEAH |
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| 07 Sep 2014 09:52 PM |
are you in 6th grade?
lol!!! xdd |
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| 07 Sep 2014 09:52 PM |
| But maybe you should go in to see your teacher for help. |
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The96
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| Joined: 29 Jul 2013 |
| Total Posts: 267 |
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| 07 Sep 2014 09:52 PM |
| i did it in my head so im not sure if im right |
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| 07 Sep 2014 09:52 PM |
just go to school and before school starts ask for the teachers help i did it once or twice before
Rainbowdash/Sadmiles4ever |
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| 07 Sep 2014 09:52 PM |
if it means solve for k then:
slope = y2 - y1/x2 - x1 = so 5-2k/2k-1 = 3/2
multiply 2k-1 to the other side:
5-2k = 3k - 3/2 --> solve for k
13/2 = 5k
k = 13/10 |
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waysideme
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| Joined: 19 Dec 2009 |
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| 07 Sep 2014 09:54 PM |
5-2k/2k+1-1= 5-2k/2k=3/2 5-2k(2)=2k(3)=10-4k=6k 10-4k+4k=10 6k+4k=10k 10k/10=k 10/10=1 k=1 (1,2(1)=(1,2) (2(1)+1,5)=(2+1,5)=(3,5) |
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| 07 Sep 2014 09:54 PM |
parameter k is 4.
my names ray and i like to use reapers |
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| 07 Sep 2014 09:55 PM |
CHECK YOUR WORK:
5 - 2(1) / 2(1) + 1 - 1 = 3/2
5 - 3 / 2 + 0
3 / 2 = 3 / 2
YES
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| 07 Sep 2014 09:57 PM |
| woops mean 1 i didnt see that comma |
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| 07 Sep 2014 10:05 PM |
Allow me to explain it better.
"Given A(1,2k) and B(2k+1,5) two points on line l. Determine the value of parameter k if:
The slope of l is equal to 3/2 (3 over 2)"
Both of these points are on the line, and that line has a slope of 3/2.
The Easiest way to find what K is, is naturally to solve for them.
--- Point slope form (AND/OR the SLOPE FORMULA) is used for two points on a line and is used to find the slope. Since you already know the slope, you can use it to solve for k.
m = y - y1 / x - x1 where (x, y) and (x1, y1) are two individual points on the line.
We'll say A = x1,y1 and B = x, y
Substitute the values. - A(1,2k) and B(2k+1,5)
3/2 = (5) - (2k)/ (2k+1) - 1
3 = 5 - 2k --=-------- 2 = 2k + 1 - 1 (1 - 1 = 0, cancel)
Cross multiply so that 2(5-2k) = 3(2k)
Distribute so that 10 - 4k = 6k
Add 4k to both sides (because it's easier) and Divide by ten
k = 1.
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