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| 13 May 2014 01:30 PM |
Rules;
Must work ALONE no help
Must have ClassName "Script"
No strings can have capital letters in them
The p@55w0rd your cracking is;
A random length (between 1 - 999 chars)
A random ammount of capital letters
A random ammount of lowercase letters
A random ammount of numbers
A random ammount of symbols
The letters picked are random
The numbers picked are random
The symbols valid are; []{}#%^*+=$&@
The characters are in a random order
Basically it's completely random.
Extra Details;
print(io.read()) is how I'm measuring length
Due to complaints I won't participate (still looking at you islandmaker2012)
You must create a brute force cracker that will crack the p@55w0rd in mere milleseconds. Goodluck! |
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BogyMac
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| Joined: 04 Nov 2011 |
| Total Posts: 823 |
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| 13 May 2014 01:32 PM |
Sorry, not related, but this is the easiest way to get to you Warspy.
Could you please read and try to figure out my post titled "???" ? |
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| 13 May 2014 01:43 PM |
just thought i'd show you this... http://imgur[dot]com/yPlQPiH.jpg
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| 13 May 2014 01:45 PM |
| @ver what's that supposed to even mean..? |
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| 13 May 2014 01:46 PM |
brute force cracking a p@55, its how long it usually takes for a decent p@55
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| 13 May 2014 01:48 PM |
| That is not with technology today then. It's much faster. 5 characters would take like 5 milleseconds. |
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| 13 May 2014 01:48 PM |
then show me your example and let me test it.
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| 13 May 2014 01:51 PM |
"No strings can have capital letters in them"
Does this mean the security word only has lowercase letters? What are the constraints for the security word? Are special characters allowed (!, @, #, etc), or is it just letters or numbers? |
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| 13 May 2014 01:54 PM |
| @ver you can crack a 20 char windows p@55word in about 2 mins |
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| 13 May 2014 02:30 PM |
@agent
The original post has those details in "The p@55w0rd your cracking is;" section.
The STRINGS IN THE SCRIPT YOU MAKE can't have capitals. |
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| 13 May 2014 03:21 PM |
| I suggest you shorten the strings to at most 10 characters. You're going to be waiting a VERY long time for these. |
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| 13 May 2014 03:24 PM |
Even a six-character string is taking far too long to crack. For a brute force method. |
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cntkillme
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| Joined: 07 Apr 2008 |
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| 13 May 2014 03:31 PM |
| @cnt yes, but forum games would have no idea what he's talking about. |
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cntkillme
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| Joined: 07 Apr 2008 |
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| 13 May 2014 03:35 PM |
@DeSpizer ikr
@EVERBODYAlright. Make it a random ammount of chars 1-5 |
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powertool
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| Joined: 01 Feb 2008 |
| Total Posts: 3771 |
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| 13 May 2014 03:47 PM |
@warspyking
Good luck with that. You've given us the full printing ascii character set.
gyazo dot com slash c1ef802d37b6e0ba348bf21fc2cef2cb <---Note that I maxed out calculations per second, used the full printing ASCII character set including space, and went to 999 characters. It'd still take infinity years to calculate. |
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| 13 May 2014 03:51 PM |
Just remember...
Must work ALONE no help
•No _G.functions
•No StringValues/NumerValues/etc. already existing
•No HttpService
•etc. |
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| 13 May 2014 03:54 PM |
4 characters. Processing for over 10 minutes. Still going.
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| 13 May 2014 04:59 PM |
Maybe this was harder then I thought...
Here's a new one for ya lol. http://www.roblox.com/Forum/ShowPost.aspx?PostID=134069871 |
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cntkillme
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| 13 May 2014 06:25 PM |
It's not hard, you just aren't specific. What special characters are you allowing? a-zA-Z0-9 and !@#$%^&*() is that it? |
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| 13 May 2014 06:43 PM |
The symbols valid are; []{}#%^*+=$&@
States in the original post. |
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cntkillme
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| Joined: 07 Apr 2008 |
| Total Posts: 44956 |
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| 13 May 2014 06:55 PM |
| Then that's not hard at all then (although it may take time since brute-forcing isn't very efficient) |
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