DlSCORD
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| Joined: 28 Oct 2011 |
| Total Posts: 555 |
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| 21 Apr 2014 10:52 AM |
Does anyone know the exact force needed to lift one cubic unit of a material where the SpecificGravity is 1?
My estimate came to around 280, but I'm not sure. |
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DlSCORD
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| Joined: 28 Oct 2011 |
| Total Posts: 555 |
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| 21 Apr 2014 10:54 AM |
Bump..
I tested it on 4x4x4 cubes and 20x20x20 cubes and it comes close, but it still looks like it moved a little when I apply the opposite force. |
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RoflBread
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| Joined: 18 Jun 2009 |
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DlSCORD
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| Joined: 28 Oct 2011 |
| Total Posts: 555 |
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| 21 Apr 2014 11:39 AM |
Thanks, but that number was probably meant to be used with plastic which has a SpecificGravity of 0.7
and if you divide that number by 0.7, you get a number close to 280.3
I found that using 282 is almost exactly the force needed to counter the gravitational force.
The formula to get gravity: Gravity = -Mass*SpecificGravity*282 |
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RoflBread
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| Joined: 18 Jun 2009 |
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cntkillme
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| Joined: 07 Apr 2008 |
| Total Posts: 44956 |
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| 21 Apr 2014 11:57 AM |
196.2 is.
Test this (make sure the part is "asleep" (not moving in any way, but also not anchored)
Instance.new("BodyForce", part).force = Vector3.new(0, part:GetMass() * 196.2, 0) |
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RoflBread
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| Joined: 18 Jun 2009 |
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| 21 Apr 2014 12:21 PM |
| I'm confused because he mentioned specific gravity, which is to do with buoyancy |
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