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| 03 Apr 2014 04:26 AM |
How do I find the missing side of a triangle?
I have problems with that badly and EOCs are coming up and I want to get to high school having Geometry and Algebra I done and completed.
~Alt of the permabanned iluvmom2000, add 11k post~ |
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| 03 Apr 2014 04:27 AM |
| i don't know what is a math |
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| 03 Apr 2014 04:27 AM |
"i don't know what is a math"
I said geometry not math.
._.
(I know what u meant.)
~Alt of the permabanned iluvmom2000, add 11k post~ |
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jamkid12
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| Joined: 21 Mar 2010 |
| Total Posts: 17460 |
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| 03 Apr 2014 04:36 AM |
you can use sin,cos,tan ,pythagarus theorum and sine rule and cosine rule
depends on what the question says |
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| 03 Apr 2014 04:41 AM |
"sin,cos,tan"
I have no idea what they were.
But I googled.
No need to explain.
~Alt of the permabanned iluvmom2000, add 11k post~ |
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jamkid12
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| Joined: 21 Mar 2010 |
| Total Posts: 17460 |
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| 03 Apr 2014 04:42 AM |
also if you have the two other sides
i'd recommend using pythagoras theorum as its quicker |
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qdhxx
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| Joined: 02 Jul 2010 |
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| 03 Apr 2014 04:43 AM |
@jam
only works if there's a 90 angle
... |
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| 03 Apr 2014 04:45 AM |
"i'd recommend using pythagoras theorum as its quicker"
Thanks. It's usually Right angles on the EOC.
I forgot about that when I took it.
~Alt of the permabanned iluvmom2000, add 11k post~ |
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| 03 Apr 2014 05:06 AM |
sine= opposite/hypotenuse
cosine= adjacent/hypotenuse
tangent= opposite/adjacent
if they give you an angle and at least two sides for example\
angle =60
adjacent = 12
tan60 =x/12
(tan60)/12=x |
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| 03 Apr 2014 05:08 AM |
if you're trying to find the angle and given two sides
go tan^-1 = (opposite value)/(adjacent value) |
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