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Re: Geometry nerds help mee

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iluvsnoopy2000 is not online. iluvsnoopy2000
Joined: 01 Apr 2009
Total Posts: 3122
03 Apr 2014 04:26 AM
How do I find the missing side of a triangle?

I have problems with that badly and EOCs are coming up and I want to get to high school having Geometry and Algebra I done and completed.



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yoshiandgoomba2 is not online. yoshiandgoomba2
Joined: 21 Mar 2012
Total Posts: 22644
03 Apr 2014 04:27 AM
i don't know what is a math
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iluvsnoopy2000 is not online. iluvsnoopy2000
Joined: 01 Apr 2009
Total Posts: 3122
03 Apr 2014 04:27 AM
"i don't know what is a math"

I said geometry not math.

._.

(I know what u meant.)

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jamkid12 is not online. jamkid12
Joined: 21 Mar 2010
Total Posts: 17460
03 Apr 2014 04:36 AM
you can use sin,cos,tan ,pythagarus theorum and sine rule and cosine rule

depends on what the question says
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iluvsnoopy2000 is not online. iluvsnoopy2000
Joined: 01 Apr 2009
Total Posts: 3122
03 Apr 2014 04:41 AM
"sin,cos,tan"

I have no idea what they were.

But I googled.

No need to explain.

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jamkid12 is not online. jamkid12
Joined: 21 Mar 2010
Total Posts: 17460
03 Apr 2014 04:42 AM
also if you have the two other sides

i'd recommend using pythagoras theorum as its quicker
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qdhxx is not online. qdhxx
Joined: 02 Jul 2010
Total Posts: 56658
03 Apr 2014 04:43 AM
@jam

only works if there's a 90 angle

...
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iluvsnoopy2000 is not online. iluvsnoopy2000
Joined: 01 Apr 2009
Total Posts: 3122
03 Apr 2014 04:45 AM
"i'd recommend using pythagoras theorum as its quicker"

Thanks. It's usually Right angles on the EOC.

I forgot about that when I took it.

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warpendeshia is not online. warpendeshia
Joined: 10 Dec 2010
Total Posts: 8714
03 Apr 2014 05:06 AM
sine= opposite/hypotenuse

cosine= adjacent/hypotenuse

tangent= opposite/adjacent

if they give you an angle and at least two sides for example\

angle =60


adjacent = 12


tan60 =x/12

(tan60)/12=x
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warpendeshia is not online. warpendeshia
Joined: 10 Dec 2010
Total Posts: 8714
03 Apr 2014 05:08 AM
if you're trying to find the angle and given two sides


go tan^-1 = (opposite value)/(adjacent value)
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