xScarred
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| Joined: 14 Oct 2013 |
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| 14 Feb 2014 03:56 PM |
Literal Inequalities 3(-2 + 18) < 6(9-I+2u)
HAPPY VALENTINES |
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xScarred
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| Joined: 14 Oct 2013 |
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| 14 Feb 2014 04:01 PM |
3(-2 + 18) < 6(9-I+2u) -6 + 54 < 54-6I+12u
Wellll. |
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kyle90038
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| 14 Feb 2014 04:02 PM |
oh jesus literal inequalities are like a step above literal equations,which suck |
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xScarred
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xScarred
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KidBugs
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| 14 Feb 2014 04:25 PM |
3(-2 + 18) < 6(9-I+2u) -6 < -I + 2u - 6 + I < 2u (-6 + I)/2 < u
idk what I is, just a variable? anyways, the inequality in terms of u. this is 2 hard 4 me lel |
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KidBugs
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| Joined: 18 May 2013 |
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| 14 Feb 2014 04:26 PM |
| oh forgot to distribute the 6 to the -I |
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Glaceau1
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| 14 Feb 2014 04:26 PM |
3(-2 + 18) < 6(9-I+2u) 48 < 54 - 6I + 12u
6I < 6 + 12u
I < 2u + 1 |
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| 14 Feb 2014 04:27 PM |
3(-2 + 18) < 6(9-I+2u) -6 + 18 < 54 -I+2U 12 < 54 -I+2U + I +I 12I < 54 + 2U --------- 12 12 I < 4.5 +2U
what |
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Inversus
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| Joined: 30 Jul 2010 |
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| 14 Feb 2014 04:28 PM |
3(-2 + 18) < 6(9-I+2u)
3*-2 + 3 * 18 < 6*9 - 6*I + 6*2u
-6 + 54 < 54 - 6I + 12u
-6 + 54 - 54 < - 6I + 12u
-6 < -6I + 12u
idk what you're supposed to do since idk what that is but erm simplified it:
-1 < -I + 2u |
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| 14 Feb 2014 04:29 PM |
3(-2 + 18) < 6(9-I+2u)
-6 + 54 < 54 - 6I + 12u
48 < 54 - 6I + 12u
final answer is
24 < 27 - 3I + 6u |
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| 14 Feb 2014 04:31 PM |
oops, sorry
24 < 27 - 3I + 6u
final answer is
8 < 9 - I + 2u |
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| 14 Feb 2014 04:31 PM |
| It's okay Arliss, would you like to borrow some of my Asian? ^^ |
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| 14 Feb 2014 04:32 PM |
| ya i need to stop looking so white |
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Glaceau1
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| 14 Feb 2014 04:32 PM |
24 < 27 - 3I + 6u
This has a GCF of 3...
8< 9 - I + 6u
you want to isolate I because it is what you are searching for...
I < 6u + 1
I think you did order of operations wrong however because I got a 2u and not a 6u.. |
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xScarred
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| Joined: 14 Oct 2013 |
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| 14 Feb 2014 04:32 PM |
3(-2 + 18) < 6(9-I+2u) -6u + 54 , 54 -6I + 12u -12u - 12u -18u + 54 < 54- 6I -54 -54 -18u < -6I ---- ----- -6 -6 3u > I I <3 U |
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| 14 Feb 2014 04:33 PM |
ok i see where this is going now
8 < 9 - I + 2u
-1 < -I + 2u
yes i'm pretty sure this is the final answer
1 > I - 2u |
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| 14 Feb 2014 04:35 PM |
@Glac
When dividing by a negative number the inequality has to be flipped, so it's really
I > 2u+1 |
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xScarred
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| Joined: 14 Oct 2013 |
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| 14 Feb 2014 04:35 PM |
| I dunno xD I tried to make it up. |
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| 14 Feb 2014 04:36 PM |
"3(-2 + 18) < 6(9-I+2u) -6u + 54 , 54 -6I + 12u"
"-6u + 54 , 54 -6I + 12u"
"-6u + 54 ,"
"-6u"
where are you getting this -6u from |
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