weewoo5
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| Joined: 25 Oct 2009 |
| Total Posts: 2281 |
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| 08 Dec 2013 09:39 PM |
The mathematical community should accept the imaginary number of 1/inf as a constant of which will be called q.
For example, instead of saying that because of limits as x approaches infinite y is 0 you could instead say that if y = 7 that the result would be 7q. I assume this would have some applications in theoretical mathematics and physics. |
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XML1
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| Joined: 26 Jun 2013 |
| Total Posts: 95 |
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| 08 Dec 2013 09:42 PM |
| This is intriguing. It seems as though you misclicked, though. This is not a mathematical community. If you want people to accept your arbitrary ideas then go somewhere where people care. |
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| 08 Dec 2013 09:44 PM |
| Weewooo go away, don't come back another day. Kthx |
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weewoo5
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| Joined: 25 Oct 2009 |
| Total Posts: 2281 |
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| 08 Dec 2013 09:44 PM |
| I would love if Roblox had a forum for mathematicians, although I remain for that wish to be fulfilled, and instead must consult the closet thing to a math community. |
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| 08 Dec 2013 09:45 PM |
| Hmm, I don't know your reasoning behind using q as the constant so I don't quite agree on that part. However, a constant with the value of one divided by infinity would be quite useful. |
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weewoo5
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| Joined: 25 Oct 2009 |
| Total Posts: 2281 |
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| 08 Dec 2013 10:00 PM |
| I don't have any ideas for fancy symbols right now. So I just used a strange letter. |
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jewelycat
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| Joined: 10 Sep 2008 |
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weewoo5
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| Joined: 25 Oct 2009 |
| Total Posts: 2281 |
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| 09 Dec 2013 02:37 PM |
| Yes, it represents an infinitely small number with the value of 1/inf. But logic also states that 7/inf is larger than 6/inf |
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| 09 Dec 2013 04:23 PM |
@weewoo5 You might want to read this http://mathforum.org/library/drmath/view/62486.html |
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xSIXx
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| Joined: 06 Aug 2010 |
| Total Posts: 9202 |
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| 09 Dec 2013 05:01 PM |
"But logic also states that 7/inf is larger than 6/inf"
not this garbage again. |
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xSIXx
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| Joined: 06 Aug 2010 |
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| 09 Dec 2013 05:07 PM |
i have a feeling this post is just fluffy junk in order for this guy to sound smart.
i mean, it literally seems like he just finished a semester of pre-calc or something and is now coming up with ridiculous "theories".
if you are proposing the limit as x approaches infinity for some function like "1/x" is a constant 'q' instead of '0', you:
1. are ruining a lot of theorems in calculus. 2. don't know what a constant is. |
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| 09 Dec 2013 05:08 PM |
| A sum of an infinite series can converge on an integer. |
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| 09 Dec 2013 05:09 PM |
| ummmmmmmmmmmmmmmmmmmmmmmmmmm i dont get it |
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xSIXx
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| Joined: 06 Aug 2010 |
| Total Posts: 9202 |
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| 09 Dec 2013 05:11 PM |
"A sum of an infinite series can converge on an integer."
im pretty sure he never mentioned sumations.
he's a moron regardless. |
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mew903
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| Joined: 03 Aug 2008 |
| Total Posts: 22071 |
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| 09 Dec 2013 06:07 PM |
| op tryna fit in like hank hill at a rave |
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MettaurSp
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| Joined: 20 Mar 2010 |
| Total Posts: 3179 |
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| 09 Dec 2013 06:29 PM |
| I wanna see weewoo selling propane and propane accessories now while Kahn yells "redneck hillbilly neighbor" at him for no apparent reason. |
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| 10 Dec 2013 11:12 AM |
OP, you make no sense.
n/x for all n in R as x --> inf = 0. Always.
This also means any constant c * n/x for all n, c in R as x --> inf also = 0. Always.
Plus, even if we do use some arbitrary variable q to hold 1/x as x --> inf, q = 0 anyway, and your proposed notation of 7q = 7*0 = 0 anyway (as x --> inf).
Plus, inf isn't even a number, and thus cannot be represented in equations, so the term 1/inf is complete nonsense from the get-go. |
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| 10 Dec 2013 11:28 AM |
The correct mathematical term is that 1/infinite tends towards 0. If you think about it, it actually IS 0.
'But logic also states that 7/inf is larger than 6/inf'
wat. Infinity is NaN. Not a Number.
infinity == infinity n < infinity where n is not infinity.
All values that can possibly be written down are smaller than infinity. If you divide a number by infinity, you are not simply dividing a small number by a big number, you are dividing a small number by a concept that is bigger than anything else. Since it isn't really a number, you shouldn't really be able to divide by it, but if you did manage to, you would get 0 for absolutely ANY real number you put as the numerator. |
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| 10 Dec 2013 11:33 AM |
| So, infinity is not in the set of all real numbers? |
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| 10 Dec 2013 11:34 AM |
| Infinity isn't a number at all. It's a concept. |
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| 10 Dec 2013 11:38 AM |
| So, it's not in the set of real numbers. |
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toshir0z
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| Joined: 03 Nov 2009 |
| Total Posts: 425 |
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| 10 Dec 2013 05:50 PM |
| I propose that weewoo5 leaves this forum and never returns. |
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