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| 09 Dec 2013 08:28 PM |
Solve the linear system by substitution, elimination, or graphing.
2x + 5y = 9 y = x + 2 |
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| 09 Dec 2013 08:31 PM |
okay let me do step 1
2x + 5y = 9 -x + y = 2 |
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Flexably
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| Joined: 04 May 2012 |
| Total Posts: 15503 |
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| 09 Dec 2013 08:33 PM |
| How are we supposed to post a graph lol |
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| 09 Dec 2013 08:33 PM |
no you smell fish
step 2
2x + 5y = 9 -2x + 2y = 4 |
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Axel810
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| Joined: 31 May 2010 |
| Total Posts: 3522 |
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| 09 Dec 2013 08:34 PM |
| Oh man, this is one hard question. |
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| 09 Dec 2013 08:34 PM |
@Flex
The answer isn't in a graph, but in something like (x, y) |
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| 09 Dec 2013 08:35 PM |
| Wow, Wikipedia is great isn't it? |
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| 09 Dec 2013 08:35 PM |
2x+5y=9 -x+y=2
2x+5y=9 -2x+2y=4
7y=13
y=13/7
-x+13/7=14/7
-x=1/7
x=-1/7
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| 09 Dec 2013 08:36 PM |
| You do know most people are just going to google or yahoo this? By yahoo, I mean go to yahoo questions. |
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Paradisco
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| Joined: 17 Aug 2010 |
| Total Posts: 1231 |
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| 09 Dec 2013 08:37 PM |
ok why does everyone like elimination
substitution all the way my homies |
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Axel810
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| Joined: 31 May 2010 |
| Total Posts: 3522 |
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| 09 Dec 2013 08:37 PM |
| @why Graphing can be used to find the answer. Which is basically where both graphs intercept one another |
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| 09 Dec 2013 08:37 PM |
| Enjoy your homework points that RT contirbuted to |
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Paradisco
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| Joined: 17 Aug 2010 |
| Total Posts: 1231 |
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| 09 Dec 2013 08:38 PM |
I was hoping they would be parallel
to mess with forumers or same line |
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| 09 Dec 2013 08:42 PM |
@Axel
Yeah, but who would want to waste their time trying to find a graph format on the web? |
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| 09 Dec 2013 08:43 PM |
| It's too easy just to get a graphing calculator out for |
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QatSim
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| Joined: 24 Dec 2012 |
| Total Posts: 5009 |
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| 09 Dec 2013 08:44 PM |
2x + 5y = 9 -2x -2x
5y = -2x + 9 /5 /5
y = -2/5x + 1&4/5 |
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QatSim
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| Joined: 24 Dec 2012 |
| Total Posts: 5009 |
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| 09 Dec 2013 08:45 PM |
oh wait the other thing
I'm in algebra 1, pity me |
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