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Disav0w
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| Joined: 06 Jun 2013 |
| Total Posts: 577 |
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| 11 Nov 2013 07:04 PM |
Why is an Oder on the C&G? Go back to LMaD >_>
Fluttershy4ever |
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| 11 Nov 2013 07:04 PM |
| you kids are stupid, I had a freaking D in Chemistry in HS and I know that ain't right for sure. |
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Rhinoxus
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| Joined: 04 Oct 2013 |
| Total Posts: 462 |
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| 11 Nov 2013 07:06 PM |
| Twisted, they are attempts at chemistry jokes, I think. :) |
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| 11 Nov 2013 07:08 PM |
| Hmm, well I think the formula is some water + 32 degrees or below = ice. |
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| 11 Nov 2013 07:09 PM |
Try this.
CuSCN+KIO3+HCl === CuSO4+KCl+HCN+ICI+H2O |
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| 11 Nov 2013 07:10 PM |
IT'S OBVIOUSLY H2O2 GO TRY IT AND PUT IT ON YOUR TONGUE |
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| 11 Nov 2013 07:10 PM |
H2O(l) turns into H2O(s)
oɹq pɐɯ noʎ |
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| 11 Nov 2013 07:14 PM |
CuSCN+KIO3+HCl === CuSO4+KCl+HCN+ICI+H2O
What the hell is this witchcraft you have placed before me? Unbalenced and hellish?!?!?!?
Copper (I) thiocyanate + Potassium iodate + Hydrochloric acid yields Copper (II) Sulfate + Potassium chloride + hydrocyanic acid + (that compound, CI(2), would have a negative charge Typically it occurs as CI(2)H(2), diiodomethane. I have never seen it in that form) + water.
The equation is unbalanced. FFFFFF |
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| 11 Nov 2013 07:18 PM |
UPDATE: CI(2) 2- doesn't exist. ._.
Begone chemical interloper! |
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| 11 Nov 2013 07:21 PM |
| chemistry killed my jewish cousin |
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suskae223
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| Joined: 12 Dec 2008 |
| Total Posts: 2282 |
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NilPirate
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| Joined: 31 Jul 2010 |
| Total Posts: 3077 |
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| 11 Nov 2013 07:22 PM |
| it's just a cation, it's real because it's covalent |
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| 11 Nov 2013 07:22 PM |
@false
i bet you looked that one up, because i have no idea how the hell you got it. |
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RealPersa
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| Joined: 21 Dec 2012 |
| Total Posts: 7124 |
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| 11 Nov 2013 07:23 PM |
H2OLN2 = Ice
~مانند یک گانگستر واقعی~ |
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Acestrum
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| Joined: 11 Oct 2012 |
| Total Posts: 1728 |
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| 11 Nov 2013 07:24 PM |
False has spoken!
@Shattered. I burst out laughing. But mehh :/ |
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| 11 Nov 2013 07:27 PM |
Nono Nil, that implies that you've isolated a Carbon and bound it to only 2 iodide anions. The C would most likely bond to four iodide anions instead of simply two in a reaction. The product simply won't work.
Correctly balanced and written, the carbon/iodide compound should be carbon tetraiodide.
Also Twisted, it's called a basic chemistry education (I'm a chemistry major at university). The only thing I looked up was to verify the nonexistence of the CI(2) cation you proposed. |
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sovietz
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| Joined: 12 Jun 2013 |
| Total Posts: 13554 |
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| 11 Nov 2013 07:28 PM |
no stop no
[ TSD ]-[ Neophyte ] |
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