Arcarius
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| Joined: 28 Jul 2012 |
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| 21 Oct 2013 01:41 PM |
Two cars are travelling along a racing track. The car in front has a mass of 1400 kg and moving at 20ms-1 while the car behind has a mass of 100kg and is moving at 30ms-1 . They collide and e car in front moves off with a speed of 25 ms-1
a) determine the speed of the rear car after the collision b) show clearly whether this collision was elastic or inelastic
Do this for me and explain it and il give you 2k
ok go go go
Also this is for physics clan of roblox wink wink |
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Jack37b
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| 21 Oct 2013 01:41 PM |
#QuitButCameBack
I'm Bane. ( ° ͜ʖ °) |
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| 21 Oct 2013 01:42 PM |
i did this in class but didn't pay attention and got kicked out of the course
oh well |
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Arcarius
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| 21 Oct 2013 01:42 PM |
'#QuitButCameBack' My friends are idiots so hell no am i putting it on fb This is the next best thing |
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Jack37b
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Arcarius
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| Joined: 28 Jul 2012 |
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| 21 Oct 2013 01:43 PM |
| 'i did this in class but didn't pay attention and got kicked out of the course' classic john |
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EastC7G
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| 21 Oct 2013 01:44 PM |
b) show clearly whether this collision was elastic or inelastic
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| 21 Oct 2013 01:46 PM |
e = mc2
speed = time x distance (forgot)
mass = energy divided by speed
so
hmm
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Arcarius
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EastC7G
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| Joined: 21 Jun 2013 |
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| 21 Oct 2013 01:51 PM |
b) show clearly whether this collision was elastic or inelastic
If you show if it is elastic, you can see the damage on how it is pulled in. So type or write b and donate me |
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Arcarius
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EastC7G
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EastC7G
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| 21 Oct 2013 01:56 PM |
LOL arcarius ur thread is moved to ot
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webspace
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| 21 Oct 2013 01:59 PM |
I'll answer both for 3k
A) 23 ms-1 to the right
30000(1000x30) + 28000 (1400x20) = 1000 v + 35000 (1400 x 25) 58000 - 35000 = 1000 v 1000 v = 23000
B) Inelastic because the kinetic energy before was 730000 J and after it was 702000J, which means the loss is 28000 J
3k please |
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webspace
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| 21 Oct 2013 02:00 PM |
http://www.roblox.com/Nothing-suspicious-to-eat-item?id=113074170
here is the t-shirt |
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| 21 Oct 2013 02:00 PM |
| if he really gave any of u any money, id be surprised |
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JG13579
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| 21 Oct 2013 02:01 PM |
This is about momentum, so momentum (kg m/s) = mass (kg) × velocity (m/s) Therefore before the collision: Momentum of front car = 28000 Momentum of rear car = 3000 Total momentum: 31000
Then you work out the momentum of the front car from the new speed of 25ms. Therefore after the collision: momentum (kg m/s) = mass (kg) × velocity (m/s) Front: 35000
Conversation of momentum states that momentum is not lost during the collision, so:
Rear: Since total momentum was 31000, the front is 35000 is 4000 too large, so the rear car momentum must be MINUS 4000. Therefore the speed is -4000/100 = -40 m/s
a) -40m/s b) inelastic because velocity was not conserved
I am really not sure about this though so idk |
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webspace
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webspace
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| Joined: 25 Nov 2008 |
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| 21 Oct 2013 02:04 PM |
MOST EXCELLENT
I find Physics easier than Biology, because I'm weird like that, thanks. |
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Arcarius
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webspace
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Lulu2345
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