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Re: A math more basic than addition.

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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
10 Oct 2013 06:47 AM
Ok, so, yeah, probably one of the stupidest things ever, but meh, listen to this for a while.

[Rules:]
If a uses [op] by itself, it would be equal to a + (# of times you [op]'d it to itself.)
It must have a counterpart.(+/-, ^/sqrt)

[Self-check:]
2 [op] 2 = 4(Any operation with 2, to itself, results in 4.)

[Disproving:]
Every operation more complex than the most basic operation(addition), results in x operated by 1, is equal to x. However, if we make a more basic operation, than addition, it would break such pattern, for x ~= x+1.
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Oysi is not online. Oysi
Joined: 06 Jul 2009
Total Posts: 9058
10 Oct 2013 07:10 AM
[ Content Deleted ]
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
10 Oct 2013 07:20 AM
^ Exactly, I don't really understand how it works, but it'd be pretty cool to find a math more basic than addition.
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Oysi is not online. Oysi
Joined: 06 Jul 2009
Total Posts: 9058
10 Oct 2013 07:21 AM
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
10 Oct 2013 07:23 AM
Oysi, think of it as this. 2 + 2 + 2 + 2 + 2 = 2*5.

For the 1st rule:
This operation we're finding, which we'll nickname as "op" would do 2 [op] 2 [op] 2 [op] 2 [op] 2 = 2 + 5.
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PriorityMethod is not online. PriorityMethod
Joined: 17 Sep 2013
Total Posts: 356
10 Oct 2013 07:40 AM
function op(numbers)
return 7
end

Stupid Americans...
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
10 Oct 2013 07:42 AM
Are you kidding me?
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PriorityMethod is not online. PriorityMethod
Joined: 17 Sep 2013
Total Posts: 356
10 Oct 2013 07:44 AM
No it works
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
10 Oct 2013 07:46 AM
Get out.
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Oysi is not online. Oysi
Joined: 06 Jul 2009
Total Posts: 9058
10 Oct 2013 08:26 AM
[ Content Deleted ]
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
10 Oct 2013 08:28 AM
Well, op must be used just as how addition/multiplication/exponentiation is used.
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jobro13 is not online. jobro13
Joined: 05 Aug 2009
Total Posts: 2865
10 Oct 2013 01:03 PM
Aha!

Reminds me of the game 24.

You get a card with 4 numbers. You have to make 24 from those four numbers. Division, multiplication, addition and substraction is allowed and they are all calculated every step (so 2 + 4 + 6 / 3 = 12/3 and not 2 + 4 + 2)

Interesting idea to make a "24 solver".
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BlueTaslem is not online. BlueTaslem
Joined: 11 May 2008
Total Posts: 11060
10 Oct 2013 02:50 PM
Successor:
s(n) = n + 1
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jode6543 is not online. jode6543
Joined: 16 Jun 2009
Total Posts: 5363
10 Oct 2013 02:51 PM
I think what he is trying to say is this: if exponents are repeated multiplication, and multiplication is repeated addition, can there be an operation that addition would be a repeat of?
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rabbidog is not online. rabbidog
Joined: 27 Jun 2011
Total Posts: 804
10 Oct 2013 02:54 PM
It's x + 1

Idc if you don't get it.
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BlueTaslem is not online. BlueTaslem
Joined: 11 May 2008
Total Posts: 11060
10 Oct 2013 03:38 PM
Addition is repeated successor. As I just said.
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
10 Oct 2013 04:32 PM
It's all fine, UNTIL!!! A and B are not the same numbers.
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rabbidog is not online. rabbidog
Joined: 27 Jun 2011
Total Posts: 804
11 Oct 2013 12:03 AM
Or, if you are not working with just integers, it is:

1/infinity + 1/infinity
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
11 Oct 2013 03:45 AM
That's 0, smart one.
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noliCAIKS is not online. noliCAIKS
Joined: 08 Mar 2010
Total Posts: 917
11 Oct 2013 10:12 AM
No, it's not, because 0 * infinity = 0, not 1.
PRO TIP: don't try to simplify arithmetic operations on infinity; otherwise you'll get stuff like 2 * infinity = infinity so 2 = 1.
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
12 Oct 2013 12:53 AM
B
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ColorfulBody is not online. ColorfulBody
Joined: 17 Jun 2012
Total Posts: 2353
12 Oct 2013 03:41 AM
@Oysi

I tried to understand what he means and this is what I could understand:

Basically, he thought of the fact that 4 * 3 can be decomposed in 4 + 4 + 4. Here, you take a complex operation (multiplication, 4 * 3) and decompose it into a sequence of simpler operations (additions, 4 + 4 + 4). His idea is to take 4 + 3 and to decompose it into another simpler operation which we have no name for so far. The idea is that this would be decomposed into 4 [op] 4 [op] 4.

The logic behind this is very, very, very doubtful, but I think that's the idea he had in mind.
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
12 Oct 2013 03:49 AM
Colorful, that's pretty much, but I'd also like trying to operate 2 different numbers, which is currently out of my knowledge.
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noliCAIKS is not online. noliCAIKS
Joined: 08 Mar 2010
Total Posts: 917
12 Oct 2013 03:59 AM
You could compute the integral ∫(1)dx from -A to B?
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AndroidKitKat is not online. AndroidKitKat
Joined: 21 Sep 2013
Total Posts: 1525
12 Oct 2013 04:01 AM
How'd we reach to calculus? ;-;
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