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Re: Math help

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girlsami is not online. girlsami
Joined: 20 Dec 2007
Total Posts: 5957
08 Sep 2013 01:46 PM
I am having trouble with this one math question. Basicly I need to find out how many possible combinations this question could have.

"You are given 10 bricks. Each brick is 1 meter by 2 meters. You must build a wall that is 2 meters high and 10 meters wide. You may orient each brick vertically or horizontally." ( For horizontal bricks , 2 must be stacked on top of each other because you must use all 10 bricks and the wall must end up being a perfect rectangle.)

So could anyone help me solve this problem? Thanks

~*When life gives you lemons, Throw them back and ask for something better*~ Don't make me write your name in the death note ( ͡° ͜ʖ ͡°)
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TheExtremeForumTroll is not online. TheExtremeForumTroll
Joined: 04 Apr 2013
Total Posts: 296
08 Sep 2013 01:47 PM
Reported for asking for real life info
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RogerDaltrey is not online. RogerDaltrey
Joined: 04 Jul 2013
Total Posts: 6497
08 Sep 2013 01:48 PM
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girlsami is not online. girlsami
Joined: 20 Dec 2007
Total Posts: 5957
08 Sep 2013 01:49 PM
@Roger

I'm not sure how I would go about trying to solve this problem other then writing out every possible combination which would take forever.

~*When life gives you lemons, Throw them back and ask for something better*~ Don't make me write your name in the death note ( ͡° ͜ʖ ͡°)
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RogerDaltrey is not online. RogerDaltrey
Joined: 04 Jul 2013
Total Posts: 6497
08 Sep 2013 01:51 PM
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miaharper is not online. miaharper
Joined: 03 Jul 2012
Total Posts: 7378
08 Sep 2013 01:51 PM
I would help you but im too lazy to do word problems.
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girlsami is not online. girlsami
Joined: 20 Dec 2007
Total Posts: 5957
08 Sep 2013 01:52 PM
@Roger

We just stated the year and we are just reviewing stuff. But my grade 8 teacher failed to teach half the stuff that we are "reviewing"

~*When life gives you lemons, Throw them back and ask for something better*~ Don't make me write your name in the death note ( ͡° ͜ʖ ͡°)
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AwesomePerson9001 is not online. AwesomePerson9001
Joined: 24 Aug 2013
Total Posts: 2377
08 Sep 2013 01:53 PM
I have no clue how to do this math because I'm only in 5th grade e.e.

I'll help ya in 3 years, k?
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DeadZoneRalph is not online. DeadZoneRalph
Joined: 14 Jul 2013
Total Posts: 72
08 Sep 2013 01:54 PM
"You are given 10 bricks. Each brick is 1 meter by 2 meters. You must build a wall that is 2 meters high and 10 meters wide. You may orient each brick vertically or horizontally." ( For horizontal bricks , 2 must be stacked on top of each other because you must use all 10 bricks and the wall must end up being a perfect rectangle.)
1 meter high 2 meters wide
very simple
5 and 5
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DeadZoneRalph is not online. DeadZoneRalph
Joined: 14 Jul 2013
Total Posts: 72
08 Sep 2013 01:57 PM
but honestly
"You are given 10 bricks. Each brick is 1 meter by 2 meters. You must build a wall that is 2 meters high and 10 meters wide. You may orient each brick vertically or horizontally." ( For horizontal bricks , 2 must be stacked on top of each other because you must use all 10 bricks and the wall must end up being a perfect rectangle.)
I believe that it is this:
You are given 10 bricks. You have 10 bricks to use to build a wall 2 meters high and 10 meters wide. Ok.
Each brick is 1 meter tall, 2 meters wide.
So, it can only be 2 meters high and 10 meters wide, no less, no more.
2 meters high i'm thinking you would use 5 bricks for height, but it says it can't be more than 2 meters... So, that would be 5 meters high and 10 meters wide... But that wouldn't work.. Hm. I'm not quite sure, i'm in algebra 2 and I don't even understand this. I'll try and figure it out.
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AwesomePerson9001 is not online. AwesomePerson9001
Joined: 24 Aug 2013
Total Posts: 2377
08 Sep 2013 01:57 PM
Well, I didn't even try it due to the fact that I don't know 8th grade math. If that didn't help you please PM me on this day: 9/8/2016.

k

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AwesomePerson9001 is not online. AwesomePerson9001
Joined: 24 Aug 2013
Total Posts: 2377
08 Sep 2013 01:59 PM
I'm an average 5th grader. I'm good at scripting, etc. etc. Just not advanced triganometry or whatever the cubed math is. Though I think that the person who tried to help was correct. It's kinda simple in a way, But It's advanced in many ways. I think it should be about 40% rotated to horizontal 2x1. And 60% rotated to vertical 2x1. I don't know the exact placement though. And I roughly understand what you're trying to do.
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girlsami is not online. girlsami
Joined: 20 Dec 2007
Total Posts: 5957
08 Sep 2013 02:05 PM
If I did 10^10 then divided that by 5 would I get the correct answer or would I need to divide that answer by 4?

~*When life gives you lemons, Throw them back and ask for something better*~ Don't make me write your name in the death note ( ͡° ͜ʖ ͡°)
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girlsami is not online. girlsami
Joined: 20 Dec 2007
Total Posts: 5957
08 Sep 2013 02:10 PM
Bump. Please answer,

10^10=10,000,000,000
Divided by 5 = 2,000,000,000

or

10^10=10,000,000,000
Divided by 5 = 2,000,000,000
Divided by 4 = 500,000,000

Which is the correct answer?

~*When life gives you lemons, Throw them back and ask for something better*~ Don't make me write your name in the death note ( ͡° ͜ʖ ͡°)
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girlsami is not online. girlsami
Joined: 20 Dec 2007
Total Posts: 5957
08 Sep 2013 02:13 PM
Bump # 2

~*When life gives you lemons, Throw them back and ask for something better*~ Don't make me write your name in the death note ( ͡° ͜ʖ ͡°)
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AwesomePerson9001 is not online. AwesomePerson9001
Joined: 24 Aug 2013
Total Posts: 2377
08 Sep 2013 02:15 PM
Oh. I get this.

10^10/4. That would get you 500mil. Which you're trying to do because you want 10 hieght, and 2 length, So that would allow 500m/10+2^3 = 34mil. So that would lead you to 340mil used. So that would leave 160mil, So you divide that by 2, You get 80mil each.

160mil = 2 length.
340mil = 10 width.

So the length is 80mil, So length > width in this equasion but the total width > total length.

I still barely know how to do this, So I could be wrong. Infact the chances of me being wrong are quite high due to my age: [10.]. Around 0.56% chance of me even doing the problem correctly, So imagine the chances I got it right e.e.
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AwesomePerson9001 is not online. AwesomePerson9001
Joined: 24 Aug 2013
Total Posts: 2377
08 Sep 2013 02:16 PM
Oops, I made a mistake while I did the problem, Who cares I only got one thing mixed up and I most likely got it wrong anyway.

ur welcom if i got it rite
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