FauxBagel
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| Joined: 01 Jan 2011 |
| Total Posts: 270 |
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| 20 Jun 2013 06:52 AM |
I barely remember anything. I need your help. http://www.roblox.com/tri-item?id=119740373 I'll bump if it's done pending. |
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| 20 Jun 2013 07:13 AM |
| Give it about 4 or 5 more days OP. |
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FauxBagel
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| Joined: 01 Jan 2011 |
| Total Posts: 270 |
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| 20 Jun 2013 05:33 PM |
| Bump, need all your brain power since I can't figure this one out. Can you explain as well? Please. |
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FauxBagel
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| Joined: 01 Jan 2011 |
| Total Posts: 270 |
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| 20 Jun 2013 05:36 PM |
| And the goal is to find the missing variables. |
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FauxBagel
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| Joined: 01 Jan 2011 |
| Total Posts: 270 |
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regi900
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| Joined: 27 Aug 2011 |
| Total Posts: 134 |
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FauxBagel
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| Joined: 01 Jan 2011 |
| Total Posts: 270 |
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regi900
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| Joined: 27 Aug 2011 |
| Total Posts: 134 |
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FauxBagel
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| Joined: 01 Jan 2011 |
| Total Posts: 270 |
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| 20 Jun 2013 05:59 PM |
| What happened to you account? Did you finally get perma'd or something? |
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cheated
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| Joined: 09 Nov 2010 |
| Total Posts: 7073 |
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| 20 Jun 2013 06:03 PM |
x=12.5
y~3.45
-------------------------------- 5:10; x-5:15 x= 12.5
(x-5)^2-5^2=x-2y^2 (12.5-5)^2 - 25 = 5.59^2 x-2y=5.59 -2y=5.59-12.5 -2y=-6.9 y=3.45
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cheated
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| Joined: 09 Nov 2010 |
| Total Posts: 7073 |
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| 20 Jun 2013 06:09 PM |
first I found the easiest ratio of a side, which is 5:10.
therefore x-5= (15/2 or 7.5) x=7.5+5 x=12.5
Using Pythagoras' theorem trying to find the value of 'x-2y'
x-5^2 - 5^2 = x-2y 56.25^2-25=sqr(31.25)~5.59
therefore
x-2y~5.59 12.5-2y~5.59 -2y~5.59-12.5 -2y ~ -6.9 y ~ 3.45 |
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FauxBagel
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| Joined: 01 Jan 2011 |
| Total Posts: 270 |
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| 20 Jun 2013 06:09 PM |
| Thanks! You're a big help. |
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| 20 Jun 2013 06:10 PM |
| who dafuq actually does this stuff |
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cheated
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| Joined: 09 Nov 2010 |
| Total Posts: 7073 |
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| 20 Jun 2013 06:12 PM |
Would've used rational numbers. such as 1sqr2 But I find the direct way easier to comprehend. |
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regi900
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| Joined: 27 Aug 2011 |
| Total Posts: 134 |
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| 20 Jun 2013 06:17 PM |
| The actual answer is -7 he's lying |
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cheated
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| Joined: 09 Nov 2010 |
| Total Posts: 7073 |
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| 20 Jun 2013 11:41 PM |
| lol nob where is your proof |
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| 20 Jun 2013 11:41 PM |
this isn't trig
this is geometry |
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cheated
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| Joined: 09 Nov 2010 |
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| 20 Jun 2013 11:44 PM |
well barely
there's no sine, cosine, tangent, cotangent, secant, or cosecant
i remember this in geometry |
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cheated
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| Joined: 09 Nov 2010 |
| Total Posts: 7073 |
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| 20 Jun 2013 11:46 PM |
Trig is an integral part in geometry.
You use trig to solve geometry. Pythagoras theorem is in trigonometry, and solving triangle ratios are there as well. |
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JFKILLS34
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| Joined: 28 Aug 2008 |
| Total Posts: 12832 |
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| 20 Jun 2013 11:55 PM |
x=5/2; y=35/22 ~~ You have two equations: 1. (x-5)/(x-2y)=15/(x+y) 2. (x-5)/5=15/10 -- 2. is first. (x-5)/5=15/10 (x-5)/5=3/2 15=2(x-5) 15=2x-10 5=2x x=5/2, or 2.5 -- 1. is next. I plugged in x for 5/2, see? (x-5)/(x-2y)=15/(x+y) (2.5-5)/(2.5-2y)=15/(2.5+y) -2.5/(2.5-2y)=15/(2.5+y) -2.5(2.5+y)=15(2.5-2y) -6.25-2.5y=37.5-30y 43.75-30y=-2.5y 43.75=27.5y y=35/22 or ~1.59 |
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JFKILLS34
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| Joined: 28 Aug 2008 |
| Total Posts: 12832 |
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| 21 Jun 2013 12:01 AM |
Cheated, you're wrong because you used the Pythagorean Theorem on an acute triangle rather than a right triangle, where the theorem is /only/ used.
Also, this isn't trigonometry because although it involves angles and sides of a triangle, does not involve the interdependence between them, involving sin, cos, tan, and other trigonometric functions to relate each.
Sorry I came so late. qq I doubt anyone cares at this point. |
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regi900
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| Joined: 27 Aug 2011 |
| Total Posts: 134 |
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| 21 Jun 2013 01:56 AM |
| I care. Your right. And that guy was probably trying to cheat on homework or such, so he got it wrong. |
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fellex
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| Joined: 27 May 2008 |
| Total Posts: 16686 |
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