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| 08 Jun 2013 02:07 PM |
| I feel like I marked "NO CHANGE" too much on the English section |
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| 08 Jun 2013 02:13 PM |
ACTs
Not a popular subject I see
Bump |
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JFKILLS34
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| Joined: 28 Aug 2008 |
| Total Posts: 12832 |
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| 08 Jun 2013 02:15 PM |
I just love their math. No sarcasm is intended. Now find me all solutions to the equation 81^((x^3)+(2x^2))=27^(5x/3). Woof. |
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Sharky98
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| Joined: 05 Dec 2008 |
| Total Posts: 9128 |
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| 08 Jun 2013 08:08 PM |
> 81^((x^3)+(2x^2))=27^(5x/3).
Enjoy your completed homework!
81^(x^3 + 2x^2) = 27^(5x / 3)
(3^4)^(x^3 + 2x^2) = (3^3)^(5x / 3)
3^[4(x^3 + 2x^2)] = 3^[3(5x / 3)]
3^(4x^3 + 8x^2) = 3^(5x)
4x^3 + 8x^2 = 5x
4x^3 + 8x^2 - 5x = 0
x(4x^2 + 8x - 5) = 0
x(2x - 1)(2x + 5) = 0
x = -5/2, 0, 1/2 |
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JFKILLS34
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| Joined: 28 Aug 2008 |
| Total Posts: 12832 |
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| 08 Jun 2013 08:12 PM |
"Enjoy your completed homework!" It wasn't homework. I have some Baron's book about Trigonometry and Algebra II with questions and answers; I got it right though, but thank you. (I usually show work at 3^(4x^3 + 8x^2) = 3^(5x) by getting the logarithm of both sides, then dividing log 3 on both sides. I don't know if that's completely unnecessary, though.) |
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Sharky98
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| Joined: 05 Dec 2008 |
| Total Posts: 9128 |
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| 08 Jun 2013 08:14 PM |
the thing with algebra its mostly showing your work and logically breaking down the problem, so in the case the answer is wierd or something you can backtrack and find the issue
my two tix |
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